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xxMikexx [17]
3 years ago
15

What is the width of 4 1/4

Mathematics
1 answer:
astra-53 [7]3 years ago
6 0
6 2/3 x 3 1/2 = 23 1/3
so to find the second table you would use the expression

4 1/3 x width=23 1/3
width=23 1/3 divided by 4 1/4
width=5 25/51
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In a chess tournament, each player is in one game with every other player. How many games will be played if there are 7 players
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4 years ago
The mean sustained wind velocity, v, can be determined by the equation , where p is the air pressure, in millibars, at the cente
inn [45]

The mean sustained wind velocity has the equation:

v = 6.3 √(1013 - p)


If we are given with the mean sustained wind velocity of 64 m/s, then we can solve for the air pressure using the equation:

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8 0
3 years ago
Read 2 more answers
A company receives shipments of a component used in the manufacture of a component for a high-end acoustic speaker system. When
Tanya [424]

Answer:

ME= 2.33*\sqrt{\frac{0.096*(1-0.096)}{250}}= 0.0434

Step-by-step explanation:

For this case we have a sample size of n = 250 units and in this sample they found that 24 units failed one or more of the tests.

We are interested in the proportion of units that fail to meet the company's specifications, and we can estimate this with:

\hat p = \frac{24}{250}= 0.096

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The confidence interval for a proportion is given by this formula  

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}  

For the 98% confidence interval the value of \alpha=1-0.98=0.02 and \alpha/2=0.01, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=2.33  

And the margin of error would be:

ME= 2.33*\sqrt{\frac{0.096*(1-0.096)}{250}}= 0.0434

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4 years ago
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3 0
4 years ago
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vladimir2022 [97]
???? Can you be more specific please
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3 years ago
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