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Hunter-Best [27]
3 years ago
8

What do spindle fibers do during mitosis?

Biology
1 answer:
zvonat [6]3 years ago
4 0
They attach to the chromosomes, line them up during metaphase, and pull them apart during anaphase
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1. Predict: Suppose that a virus infects a small population of bacteria. Predict how the numbers of viruses, infected cells, and
lapo4ka [179]

Answer:

Viruses: stay the same

Infected cells: Increase

Unaffected cells: decrease

Explanation:

4 0
2 years ago
The two processes that move the most amount of carbon through the carbon cycle are? a.photosynthesis and respiration b. decompos
goblinko [34]

Answer:

Photosynthesis and Respiration

Explanation:

In photosynthesis C is used in the form of CO2.

In respiration C is released in the form of CO2.

7 0
3 years ago
Plants use sunlight to convert nutrients into energy. What form of energy transfer is taking place?
krok68 [10]

Answer:

Osmosis is the form of energy.

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7 0
3 years ago
What two pigments together create the color in golden-brown algae?
Svetllana [295]
ANSWER: C). Chlorophyll and carotenoids
6 0
3 years ago
Read 2 more answers
Alu element at the PV92 locus on Chromosome 16. In this population, 436 people have a heterozygous genotype and 102 people have
Lesechka [4]

Answer:

Explanation:

According to the exercise we can infer that for the Alu insert:

p: positive allelic frequency

q: negative allelic frequency

maintaining that the population is in equilibrium we can carry out the following formula

p + q = 1 and pp + 2pq + qq = 1

looking for the genotype frequency we clear and obtain the following data

genotype frequency of 2pq = 436/1000 = 0.436

The genotype frequency of qq = 102/1000 = 0.102

This is how we look now:

number of positive people for Alu = 1000- (436 + 102) = 1000- 538 = 46

In this way it is resolved that:

genotypic frequency of pp = 462/1000 = 0.462

  p = 0.462 + (0.436 / 2) = 0.462 + 0.218 = 0.680

q = 0.102+ (0.436 / 2) = 0.102 + 0.218 = 0.320

According to the exercise carried out it is deduced:

The value of p in the population is = 0.68

We conclude that our prognosis showing a homozygous positive genotype is: 0.462

6 0
3 years ago
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