Answer:
The probability of getting a mottled offspring is 0%. There is no A2 allele involved in the cross.
Explanation:
<u>Available data</u>:
- The gene for petal color in a flower has incomplete dominance 
- Two A1 alleles (A1A1) express black color
- Two A2 alleles (A2A2) express white color 
- One of each allele (A1A2) express mottled color
In a cross between two black flowers, there is no allele A2, there are just two alleles A1. So, the cross is:
Parental)    A1A1    x    A1A1
Gametes)  A1   A1       A1   A1
Punnet Square)     A1         A1
                    A1     A1A1     A1A1
                    A1     A1A1     A1A1
F1 Phenotypes: 100% black flowers
F1 Genotype: 100% A1A1
There are 0% of probabilities of getting a mottled offspring. 
 
        
                    
             
        
        
        
Answer:
 stomach, pancreas and small intestine 
 
        
             
        
        
        
Answer:
The optimum pH of ATP synthase is 6.4 therefore maximum activity  will  occur at pH7  by the vesicle, however because the concentration of the  three , is relatively the same , and exhibited  equal effects  on  the pH,  catalysis  by the vesicle will  not take place BECAUSE NO  HYDROGEN ION IS AVAILABLE  to supply the energy 
Generally the synthase activity decreases with drops in pH. The lower pH  of 6.5 from the  set point value , will affect catalysis.
The low pH     lead to  increase in  concentration of base in  the buffer solution. Therefore more H +  are produced .for the synthesis of ATP. The  vesicle catalyzed ATP production.  But the increase in hydrogen ion concentration with time  affect the 3 dimensional structure of the ATPase synthase enzyme in the vesicle and increases the inhibitory effect of ADP therefore  the  vesicle stops the catalysis.