Answer:
The probability of getting a mottled offspring is 0%. There is no A2 allele involved in the cross.
Explanation:
<u>Available data</u>:
- The gene for petal color in a flower has incomplete dominance
- Two A1 alleles (A1A1) express black color
- Two A2 alleles (A2A2) express white color
- One of each allele (A1A2) express mottled color
In a cross between two black flowers, there is no allele A2, there are just two alleles A1. So, the cross is:
Parental) A1A1 x A1A1
Gametes) A1 A1 A1 A1
Punnet Square) A1 A1
A1 A1A1 A1A1
A1 A1A1 A1A1
F1 Phenotypes: 100% black flowers
F1 Genotype: 100% A1A1
There are 0% of probabilities of getting a mottled offspring.
Answer:
stomach, pancreas and small intestine
Answer:
The optimum pH of ATP synthase is 6.4 therefore maximum activity will occur at pH7 by the vesicle, however because the concentration of the three , is relatively the same , and exhibited equal effects on the pH, catalysis by the vesicle will not take place BECAUSE NO HYDROGEN ION IS AVAILABLE to supply the energy
Generally the synthase activity decreases with drops in pH. The lower pH of 6.5 from the set point value , will affect catalysis.
The low pH lead to increase in concentration of base in the buffer solution. Therefore more H + are produced .for the synthesis of ATP. The vesicle catalyzed ATP production. But the increase in hydrogen ion concentration with time affect the 3 dimensional structure of the ATPase synthase enzyme in the vesicle and increases the inhibitory effect of ADP therefore the vesicle stops the catalysis.
