Answer:
which are present in the cell
Explanation:
of body in the base of kidney
Answer:
a) The expected phenotype of the F1 plants is 100% RrBb, red kernels.
b) The expected phenotypic classes in the F2 are: 9:3:3:1
9/16 R-B-, 3/16 rrB-, 3/16 R-bb, 1/16 rrbb
Proportions 9:6:1.
9/16 Red kernel (R-B-), 6/16 Brown kernel (rrB- + R-bb), 1/16 White kernel (rrbb)
Explanation:
<u>Available data:</u>
- brown kernel: R-bb or rrB-
1º Cross) RRBB x rrbb
F1) 100% RrBb (red kernels)
2ºCross) RrBb x RrBb
Gametes) RB RB
Rb Rb
rB rB
rb rb
Punnet Square) RB Rb rB rb
RB RRBB RRBb RrBB RrBb
Rb RRBb RRbb RrBB Rrbb
rB RrBB RrBb rrBB rrBb
rb RrBb Rrbb rrBb rrbb
F2) Phenotypic classes:
<em>9/16 R-B-</em>
<em> 3/16 rrB-</em>
<em> 3/16 R-bb</em>
<em> 1/16 rrbb</em>
Phenotypic proportions:
<em>9/16 Red kernel (R-B-)</em>
<em> 6/16 Brown kernel (rrB- + R-bb)</em>
<em> 1/16 White kernel (rrbb) </em>
controll is your awser you vary a factor to measure the results
Answer:
See the answer below
Explanation:
<em>The chance that a child from two people with sickle cell trait will have normal RBCs remains the same irrespective of the amount of oxygen in the environment.</em> From the cross:
AS x AS
AA AS AS SS
Hence, the chance of having a child with normal RBCs in both high and low-oxygen environments is 1/4 or 25%.
The chance that a child will have sickle cell disease is also 1/4 or 25%.
The possible genotypes in a Punnet's square can be seen in the attached image
