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ira [324]
3 years ago
11

A car can travel 476 miles on 14 gallons of gas write an equation relating the distance d to the number of gallons g how many ga

llons of gas does this car need to travel 578 miles
Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
8 0
The car gets 34 miles per gallon (476/14 = 34)
d=578
g=gallons needed
34 = miles per gallon

Solving for g......
578 = 34g
578/34= g
<span>g = 17</span>
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Consider a value to be significantly low if its z score less than or equal to minus−2 or consider a value to be significantly hi
katrin2010 [14]

Answer:

Test scores of 10.2 or lower are significantly low.

Test scores of 31.4 or higher are significantly high.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 20.8, \sigma = 5.3

Identify the test scores that are significantly low or significantly high.

Significantly low

Z = -2 and lower.

So the significantly low scores are thoses values that are lower or equal than X when Z = -2. So

Z = \frac{X - \mu}{\sigma}

-2 = \frac{X - 20.8}{5.3}

X - 20.8 = -2*5.3

X = 10.2

Test scores of 10.2 or lower are significantly low.

Significantly high

Z = 2 and higher.

So the significantly high scores are thoses values that are higherr or equal than X when Z = 2. So

Z = \frac{X - \mu}{\sigma}

2 = \frac{X - 20.8}{5.3}

X - 20.8 = 2*5.3

X = 31.4

Test scores of 31.4 or higher are significantly high.

3 0
3 years ago
what is an equation of the line that s perpendicullar to y-3=-4(x+2) and passes through the point (-5,7)
Sidana [21]

Answer:

4y=x+33

y=x/4+33/4 (slope-intercept form)

Step-by-step explanation:

y-3 = -4(x+2)

y-3 -4x-8

y= -4x-8+3

y= -4x-5

m1 = -4

For perpendicularity

m2= -1/-4 = 1/4

The equation is

y-y1 = m2(x-x1)

y-7 = 1/4(x-(-5))

y-7 = x/4+5/4

Multiply through by 4

4y-28=x+5

4y=x+5+28

4y=x+33

Divide through by 4

y=x/4+33/4 (slope-intercept form)

7 0
3 years ago
Relations expressed as ordered pairs are?
romanna [79]
The relations are domain and range
5 0
3 years ago
Simplify:
svetlana [45]

Answer:

−(7p+6)−2(−1−2p) = - 3p - 4

Step-by-step explanation:

−(7p+6)−2(−1−2p) = -7p - 6 + 2 + 4p

                            = (-7p + 4p) + (2 - 6)

                            = -(7p - 4p) - (6 - 2)

                           = - 3p - 4

7 0
2 years ago
Which of these systems has one unique solution?
Shtirlitz [24]

Answer:

D

Step-by-step explanation:

A,B,and C can not solve. because they have wrong answers.

6 0
4 years ago
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