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3 years ago

13

Explain why the flow of a compressed gas must be controlled for practical and safe use? use

1 answer:

dlinn [17]3 years ago

8 0

Compressed gas is pressurized, which means it has very high pressure and can flow out really quickly in huge amounts which makes it very dangerous if it is not controlled correctly.

That's why <span>the flow of a compressed gas must be controlled for practical and safe use.</span>

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What do all decomposition reactions have in common? (My answer: D, correct?)

inn [45]

Correct answer is D.

,,They start with one reactant and end with more than one product."

:-) ;-)

3 0

3 years ago

Read 2 more answers

How long does it take to electroplate 0.5 mm of gold on an object with a surface area of 31 cm^^ from an Au3+(aq) solution with

konstantin123 [22]

Answer:

It will take 5492 seconds to electroplate 0.5 mm of gold on an object .

Explanation:

Mass of gold = m

Volume of gold = v

Surface area on which gold is plated = $a=31 cm^2$

Thickness of the gold plating = h = 0.5 mm = 0.05 cm

1 mm = 0.1 cm

$V=a\times h=31 cm^2\times 0.05 cm=1.55 cm^3$

Density of the gold = $d=19.3 g/cm^3$

$m=d\times v=19.3 g/cm^3\times 1.55 cm^3=29.915g$

Moles of gold = $\frac{29.915 g}{197 g/mol}=0.152 mol$

$Au^{3+}+3e^-\rightarrow Au$

According to reaction, 1 mole of gold required 3 moles of electrons,then 0.152 moles of gold will require :

$\frac{3}{1}\times 0.152 mol=0.456 mol$ of electrons

Number of electrons = N = $0.456\times \times 6.022\times 10^{23}$

Charge on single electron = $q=1.6\times 10^{-19} C$

Total charge required = Q

$Q=N\times q$

Amount of current passes = I = 8 Ampere

Duration of time = T

$I=\frac{Q}{T}$

$T=\frac{N\times q}{I}$

$=\frac{0.456\times \times 6.022\times 10^{23}\times 1.6\times 10^{-19} C}{8 A}=5492 s$

It will take 5492 seconds to electroplate 0.5 mm of gold on an object .

7 0

3 years ago

Can reactions be more than one of the five types

ehidna [41]

Yes you can it will not just have 5 :)

3 0

3 years ago

A liquid occupies a volume of 5.0 L has a mass of 6.0 kg. what is the density of a the lights in kg/L

grandymaker [24]

Answer:

Hey there! :

Volume = 5.0 L

mass = 6.0 Kg

Therefore:

Density = mass / Volume

Density = 6.0 / 5.0

Density = 1.2 kg/L

6 0

3 years ago

What is the number of moles in 3.0 X 10^24 atoms of Carbon

evablogger [386]

Answer:the number of moles represented by 3.0 x 10^24 atoms of Ag is 0.500mol 0.500 m o l .

Explanation:

4 0

1 year ago