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Greeley [361]
2 years ago
11

Instruction

Chemistry
2 answers:
siniylev [52]2 years ago
6 0

Answer:

A: 1

B: 2

C: 1

D: 1

Explanation:

I did the question on edge 2020 :>

valkas [14]2 years ago
4 0

Answer:

A: object 1

B: object 2

C: object 1

D: object 1

Explanation:

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Four processes that change rock from one type to another.
Cloud [144]
Erosion
waethring
deposition
pressure or heat 
all of this can change the form of rock to another
8 0
2 years ago
Which statement describes the light reaction of photosynthesis?
cupoosta [38]

Answer:

A

Explanation:

water molecules are combined to make food

5 0
3 years ago
Identify the compound that would have the highest osmotic pressure when dissolved in water. nacl k2so4 mgcl2 fecl3 mgso4
brilliants [131]

The compound that would have the highest osmotic pressure when dissolved in water is FeCl_{3} .

So,  option D is correct one.

The dissociation of one molecule of  FeCl_{3} gives the maximum number of ions when dissolved in water ( 4 ions ) . Osmotic pressure is a colligative property and depends upon number of solute particles present in the solution . The solution having maximum number of solute particles will have maximum number of the osmotic pressure .

All other given molecules gives less number of number of ions when dissolved in water as compare to of  FeCl_{3} .

To learn more about osmotic pressure

brainly.com/question/10046758

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5 0
2 years ago
What is the percent of Cr in Cr2O3
IgorLugansk [536]
The percentage of Chromium in Chromium Oxide is calculated as follow,

Step 1:
           Calculate Molar mass of Cr₂O₃,
Cr = 51.99 u
O = 16 u
So,
     2(51.99) + 3(16) = 103.98 + 48 = 151.98 u

Step 2:
          Secondly divide molar mass of only chromium with total mass of Cr₂O₃ and multiply with 100.
i.e.
                   = \frac{103.98}{151.98} × 100
                   
                   = 68.41 %
So, the %age composition of chromium in chromium oxide is 68.41 %.
5 0
3 years ago
Read 2 more answers
2
son4ous [18]

Answer: The molar enthalpy change is 73.04 kJ/mol

Explanation:

HCl+NaOH\rightarrow NaCl+H_2O

moles of HCl= molarity\times {\text {vol in L}}=0.415mol/L\times 0.1=0.0415mol

As NaOH is in excess 0.0415 moles of HCl reacts with 0.0415 moles of NaOH.

volume of water = 100.0 ml + 50.0 ml = 150.0 ml

density of water = 1.0 g/ml

mass of water = volume \times density=150.0ml\times 1.0g/ml=150.0g

q=m\times c\times \Delta T

q = heat released

m = mass  = 150.0 g

c = specific heat = 4.184J/g^0C

\Delta T = change in temperature = 4.83^0C

q=150.0\times 4.184\times 4.83

q=3031.3J

Thus 0.0415 mol of HCl produces heat = 3031.3 J

1 mol of HCL produces heat = \frac{3031.3}{0.0415}\times 1=73043.3J=73.04kJ

Thus molar enthalpy change is 73.04 kJ/mol

8 0
3 years ago
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