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uranmaximum [27]
3 years ago
7

Si una masa dada de hidrógeno ocupa 40 litros a 700 grados torr. ¿Qué volumen ocupará a 1 atmósfera de presión? (dar la presión

en atmósferas). Por favor :c
Chemistry
2 answers:
Svetach [21]3 years ago
7 0

Answer:

V_2=36.84L

Explanation:

Hola,

En este caso, podemos usar la ley de Boyle, la cual nos permite analizar el comportamiento volumen-presión en un gas ideal de manera inversamente propocional:

P_1V_1=P_2V_2

Así, dado el volumen y la presión inicial, la cual se convierte a atmósferas (760 torr = 1atm), calculamos el volumen final a 1 atm como se muestra a continuación:

V_2=\frac{P_1V_1}{P_2}=\frac{700torr*\frac{1atm}{760torr}*40l }{1atm}\\  \\V_2=36.84L

Saludos!

MissTica3 years ago
5 0

Answer:

V_2=~36.84~Litros

Explanation:

En este caso tenemos diferentes valores de volumen y presión para un <u>primer estado</u>:

V_1=~40~Litros

P_1=~700~torr

Y tenemos valores de presión para un <u>segundo estado</u>:

V_2=~?

P_2=~1~atm

Necesitamos una relación entre volumen y presión para poder hallar nuestra incognita ( V_2). Nuestra relación es la <u>ley de Boyle</u>:

P_1*V_1=P_2*V_2

Ahora bien, tenemos una unidad diferente para el presión en P_2 (atm), debemos hacer una <u>conversión</u>. Esta conversión puede hacerse si sabemos que <u>1 atm = 760 torr</u> por lo cual P_2=760~torr

Ahora podemos <u>reemplazar en la ecuación</u>:

700~torr*40~Litros=760~torr*V_2

V_2=\frac{700~torr*40~Litros}{760~torr}

V_2=~36.84~Litros

El volumen sera de <u>36.84 Litros</u>

Espero que ayude!

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