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Olin [163]
3 years ago
13

What is the easiest way to find the charge of an element using the periodic table?!?

Chemistry
1 answer:
gizmo_the_mogwai [7]3 years ago
7 0
<span>On the Periodic Table metals are found on the left of the table and will be positive, while non-metals are found on the right of the table and will be negative. </span>
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Bill, a lab technician, was asked to measure out sodium hydroxide (NaOH) for an experiment in a research lab. He was given a cho
Aleks04 [339]

Answer:

He is wrong . Most accurate is Buret .

Explanation:

The number of significant figure denotes the level of accuracy of a measurement .

Beaker can measure liquid in mL upto significant figure of 2 . That means it can measure volume in terms of 10 , 20 , 30mL etc . It can not measure 25 mL

accurately . The last figure of 28 mL is read by guess in the question . So it is not an accurate measurement .

Similarly , graduated cylinder can measure liquid upto significant figure of 3 .  That means it can measure volume in terms of 11 , 22 , 33 mL etc . It can not measure 25.5  mL accurately . The last figure of 28.3  mL is read by guess in the question . So it is less  accurate measurement .

Similarly , buret  can measure liquid upto significant figure of 4 .  That means it can measure volume in terms of 11.2 , 22.3 , 33.5 mL etc . It can not measure 25.53  mL accurately . The last figure of 28.32  mL is read by guess in the question . So it is most accurate among all the three instrument because it can measure accurately mL upto one tenth of it .

7 0
3 years ago
In an electroplating process, copper (ionic charge +2e, atomic weight 63.6 g/mol) is deposited using a current of 10.0 A. What m
salantis [7]

Answer : The mass of copper deposit is, 1.98 grams

Explanation :

First we have to calculate the charge.

Formula used : Q=I\times t

where,

Q = charge = ?

I = current = 10 A

t = time = 10 min = 600 sec      (1 min = 60 sec)

Now put all the given values in this formula, we get

Q=10A\times 600s=6000C

Now we have to calculate the number of atoms deposited.

As, 1 atom require charge to deposited = 2\times (1.6\times 10^{-19})  

Number of atoms deposited = \frac{(6000)}{2\times(1.6\times 10^{-19})}=1.875\times 10^{22} atoms

Now we have to calculate the number of moles deposited.

Number of moles deposited = \frac{(1.875\times 10^{22})}{(6.022\times 10^{23})}=0.03113 moles

Now we have to calculate the mass of copper deposited.

1 mole of Copper has mass = 63.5 g  

Mass of Copper Deposited = 63.5\times 0.03113 =1.98g

Therefore, the mass of copper deposit is, 1.98 grams

5 0
3 years ago
The number of protons plus the number of neutrons equal the ______
NARA [144]
the answer is: Atomic number
7 0
3 years ago
Read 2 more answers
Which of the following 0.300 M solutions would contain the highest concentration of potassium ions?
mojhsa [17]

Here is a list of 0.300 M solutions that you can consider to select which has the highest concetration of potassium ions:

Select one:

a. potassium oxide

b. potassium phosphate

c. potassium hydrogen carbonate

d. potassium hypochlorite

e. potassium iodide

Answer:

  • <em><u>Option b. potassium phosphate</u></em>

Explanation:

First, you must write the chemical formula of each one of the potasssium compounds. Then, assume all the compounds ionize 100%.

Since all the solutions have the same concentrations, by assuming 100% ionization, the ionization equations will show which one produces the highest number of <em>potassium ions</em>, K⁺¹, and that is the solution with the highest concentration of such ions.

<u>1. Chemical formulae</u>

Compound                                              Formula

a. <em>potassium oxide         </em>                          K₂O                                

b. <em>potassium phosphate</em>                          K₃PO₄    

c. <em>potassium hydrogen carbonate</em>          KHPO₃

d. <em>potassium hypochlorite  </em>                     KClO₄

e. <em>potassium iodide     </em>                             KI

<u>2. Dissociation (ionization):</u>

  • a. <em>potassium oxide</em>, K₂O

           K₂O does not dissociate but react with water to product KOH, then KOH dissociates, but there is not such thing as a 0.300 M solution of K₂O.

  • b. <em>potassium phosphate</em>:

       K₃PO₄ → 3K³⁺ + PO₄¹⁻                3 K⁺¹ ions per unit formula

  • c. <em>potassium hydrogen carbonate</em>          

       KHPO₃ →  K⁺¹ + HPO₃⁻¹               1 K⁺¹ ion per unit formula

  • d. <em>potassium hypochlorite </em>                      

        KClO₄ → K⁺¹ + HClO₄⁻¹                1 K⁺¹  ion per unit formula

  • e.<em> potassium iodide</em>                                  

          KI → K⁺¹ + I⁻¹                                1 K⁺¹ ion per unit formula.

Hence, the 0.300 M solution of potasssium phosphate produces the highest concentration of potassium ions.

6 0
4 years ago
Consider the malate dehydrogenase reaction from the citric acid cycle. Given the listed concentrations, calculate the free energ
Ahat [919]

<u>Answer:</u> The Gibbs free energy of the reaction is 21.32 kJ/mol

<u>Explanation:</u>

The chemical equation follows:

\text{Malate }+NAD^+\rightleftharpoons \text{Oxaloacetate }+NADH

The equation used to Gibbs free energy of the reaction follows:

\Delta G=\Delta G^o+RT\ln K_{eq}

where,

\Delta G = free energy of the reaction

\Delta G^o = standard Gibbs free energy = 29.7 kJ/mol = 29700 J/mol  (Conversion factor: 1 kJ = 1000 J)

R = Gas constant = 8.314J/K mol

T = Temperature = 37^oC=[273+37]K=310K

K_{eq} = Ratio of concentration of products and reactants = \frac{\text{[Oxaloacetate]}[NADH]}{\text{[Malate]}[NAD^+]}

\text{[Oxaloacetate]}=0.130mM

[NADH]=2.0\times 10^2mM

\text{[Malate]}=1.37mM

[NAD^+]=490mM

Putting values in above expression, we get:

\Delta G=29700J/mol+(8.314J/K.mol\times 310K\times \ln (\frac{0.130\times 2.0\times 10^2}{1.37\times 490}))\\\\\Delta G=21320.7J/mol=21.32kJ/mol

Hence, the Gibbs free energy of the reaction is 21.32 kJ/mol

4 0
3 years ago
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