Answer:
Assuming you combingin like terms
3x-6+3y
Answer:
The answer is given below
Step-by-step explanation:
The equation of a quadratic function is given by:
Ax² + Bx + C where A, B and C are the coefficients of the quadratic equation. If the coefficient of x² (i.e A) is a negative value then the graph opens down, the value of C determines the y intercept.
The equation of a parabola with y-intercept greater than 3 and opens down can be given as -2x² -6x + 4. Since the coefficient of x² is negative it opens down and C = 4, it has a y intercept of 4 > 3
Let us assume a vertical stretch of 2, the new equation becomes:
2(-2x² -6x + 4)
-4x² - 12x + 8
To solve:
-4x² - 12x + 8 = 0
A = -4, B = -12 and C = 8
Using the quadratic formula:
(x + 7)/2 - (x + 4)/2 = (x + 7 - (x + 4)/2 = (x + 7 - x - 4)/2 = 3/2
Answer:
slope= ⅗
Step-by-step explanation:
Rewrite the equation into the slope-intercept form, y=mx +c, where m is the gradient and c is the y-intercept.
3x- 5y= 0
<em>+5y on both sides of the equation:</em>
5y= 3x
<em>Divide both sides by 5:</em>
y= ⅗x
From the coefficient of x, the slope of the line is ⅗.