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Basile [38]
3 years ago
9

Stacy runs a paper chromatography experiment using the same ink, but two different solvents.

Chemistry
2 answers:
Furkat [3]3 years ago
5 0

Answer: Option C

Explanation:

Chromatography can be defined as the techniques which can be used to separate the mixture into different components. The mixture is dissolved fluid known as mobile phase.

The solid or liquid phase on which the materials are separated is known as the stationary phase.

If the solvent does not carries the ink from the original point to another point then the solvent B is not a good mobile phase and there is a strong interaction between the stationary and mobile phase.

Hence, the correct answer is option C

Pie3 years ago
4 0

Answer:

Did you ever find the answer??

Explanation:

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How does the principle of electromagnetism explain the interaction between Earth’s magnetic field and the solar wind?
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Answer:

Electromagnetism studies the attraction of two bodies within a magnetic field.

Electromagnetic interaction is one of the four fundamental forces of the known universe. The charged particles interact electromagnetically through the exchange of photons. Experimentally it was concluded that the lines of force of magnetic fields were always closed, eliminating the possibility of a magnetic monopole, so that within a magnetic field there are two poles, in the solar system the attraction between earth and wind Solar is by means of a field.

The most correct theory on this topic is the Earth itself is protected from the solar wind by its magnetic field, most of those charged particles, and most of those charged particles are trapped in the Van Allen radiation belt.

Explanation:

The magnetosphere or magnetosphere is a region around a planet in which its magnetic field deflects most of the solar wind, forming a kind of protective shield against high energy charged particles from the Sun. This magnetic or magnetosphere atmosphere does not It is only in the solar system, but also usually occurs on other planets such as jupiter and others (since it occurs on all planets with a magnetic field)

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How could you use two beakers distilled water two hot plates two thermometers and salt to test if adding salt affects the boilin
ICE Princess25 [194]
You are given two beakers, distilled water, two hot plates, two thermometers and salt. These materials are enough in order to test the effect of salt in the boiling point water. To do this, you set up two beakers. In one of the beakers, you add pure distilled water and nothing else. For the other beaker, you put a solution of salt and water. You place these beakers on separate hot plates and place inside the beakers the thermometers. You heat these substances until they boil and then you measure the boiling points of the substances. You would observe that the boiling point of the solution would have a higher boiling point than the pure liquid.
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4 years ago
Consider the following molecules and the description of the bonding present in each: CH3CH2CH2CH3CH3CH2CH2CH3 (C−CC−C and C−HC−H
denis23 [38]

CH3CH2CH2CH3 < CH3CH2CHO < CH3CHOHCH3

Explanation:

Boiling point trend of Butane, Propan-1-ol and Propanal.

Butane is a member of the CnH2n+2 homologous series is an alkane. Alkanes have C-H and C-C bonds which have Van der waals dispersion forces which are temporary dipole-dipole forces (forces caused by the electron movement in a corner of the atom). This bond is weak but increases as the carbon chain/molecule increases.

In Propan-1-ol(Primaryalcohol), there is a hydrogen bond present in the -OH group. Hydrogen bond is caused by the attraction of hydrogen to a highly electronegative element like Cl-, O- etc. This bond is stronger than dispersion forces because of the relative energy required to break the hydrogen bond. Alcohols (CnH2n+1OH) also experience van der waals dispersion forces on its C-C chain and C-H so as the Carbon chain increases the boiling point increases in the homologous series.

Propanal which is an Aldehyde (Alkanal) with the general formula CnH2n+1CHO. This molecule has a C-O, C-C and C-H bonds only. If you notice, the Oxygen is not bonded to the Hydrogen so there is no hydrogen bond but the C-O bond has a permanent dipole-dipole force caused by the electronegativity of oxygen which is bonded to carbon. It also has van der waals dispersion forces caused by the C-C and C-H as the carbon chain increases down the homologous series. The permanent dipole-dipole forces are not as easy to break as van der waals forces.

In conclusion, the hydrogen bonds present in alcohols are stronger than the permanent dipole-dipole bonds in the aldehyde and the van der waals forces in alkanes (irrespective of the carbon chain in Butane). So Butane < Propanal < Propan-1-ol

3 0
3 years ago
A heat lamp produces____<br> light.
Ipatiy [6.2K]

Answer:

infrared light

Explanation:

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