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2 years ago

1. Explain how volcanoes and earthquakes relate to each other.

2 answers:

6 0

1. Both are Very Dangerous and both are Natural Disasters. Another Similarity they have is that they cause Destructions throughout the Places they occur in

zalisa [80]2 years ago

4 0

1.Some earthquakes are associated with volcanoes. A lot of earthquakes are alongside the rims of tectonic plates. This is in which some volcanoes are too.
2. Earth changes in its personal ways. Some changes are because of gradual processes, consisting of erosion and weathering, and a few changes are because of fast processes, consisting of landslides, volcanic eruptions, Tsunamis and earthquakes. Waves, wind, water, and ice form and reshape the Earth's land surface through eroding rock in a few regions and depositing them in different regions, now and again in seasonal layers. Tectonic plates drift, the crust quakes, and volcanoes erupt. All of these effective forces form our air, land, water, and climate and are constantly reworking our planet.

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How much energy must be removed from a 94.4 g sample of benzene (molar mass= 78.11 g/mol) at 322.0 K to solidify the sample and

Kay [80]

Answer : The energy removed must be, 29.4 kJ

Explanation :

The process involved in this problem are :

$(1):C_6H_6(l)(322K)\rightarrow C_6H_6(l)(279K)\\\\(2):C_6H_6(l)(279K)\rightarrow C_6H_6(s)(279K)\\\\(3):C_6H_6(s)(279K)\rightarrow C_6H_6(s)(205K)$

The expression used will be:

$Q=[m\times c_{p,l}\times (T_{final}-T_{initial})]+[m\times \Delta H_{fusion}]+[m\times c_{p,s}\times (T_{final}-T_{initial})]$

where,

$Q$ = heat released for the reaction = ?

m = mass of benzene = 94.4 g

$c_{p,s}$ = specific heat of solid benzene = $1.51J/g^oC=1.51J/g.K$

$c_{p,l}$ = specific heat of liquid benzene = $1.73J/g^oC=1.73J/g.K$

$\Delta H_{fusion}$ = enthalpy change for fusion = $-9.8kJ/mol=-\frac{9.8\times 1000J/mol}{78g/mol}=-125.6J/g$

Now put all the given values in the above expression, we get:

$Q=[94.4g\times 1.73J/g.K\times (279-322)K]+[94.4g\times -125.6J/g]+[94.4g\times 1.51J/g.K\times (205-279)K]$

$Q=-29427.312J=-29.4kJ$

Negative sign indicates that the heat is removed from the system.

Therefore, the energy removed must be, 29.4 kJ

3 0

3 years ago

What is the role if mutations in genetic variation and the diversity of living things? Use human inheritance examples as evidenc

aliya0001 [1]

Explanation:

Mutations on DNA create genetic variation and diversity on which natural selection acts upon. Mutation can be advantageous, disadvantageous or neutral. Those mutations that confer advantage are preserved in the population while those that are DISadvantageous are weeded out. This occurs because advantageous traits that give a particular advantage to individuals in the environment, however slightest, give them an increased chance of survival and passing their genes to subsequent generations.

An example is mutation that causes sickle cell-shaped blood cells. Individuals with sickle cell blood are less likely to contract malaria. Therefore in an environment where malaria is endemic, the population will have a higher allele frequency for sickle cell alleles that populations in non-endemic areas.

Learn More:

For more on mutations check out;

brainly.com/question/11938701

brainly.com/question/13612138

#LearnWithBrainly

3 0

3 years ago

What happens to a river that’s is blocked from a landslide?

DanielleElmas [232]

Answer:

Explanation:

6 0

2 years ago

Write the symbol for every chemical element that has atomic number less than 75 and atomic mass greater than 173.5 u.

bearhunter [10]

Following are the chemical elements that have atomic mass greater than 173.5 u and atomic number less than 75.

1. Lutetium
Atomic Number = 71
Atomic Mass = 174.97 u

2. Hafnium
Atomic Number = 72
Atomic Mass = 178.49 u

3. Tantalum
Atomic Number = 73
Atomic Mass = 180.95 u

4. Tungsten
Atomic Number = 74
Atomic Mass = 183.85 u

8 0

3 years ago

16.25 g of water at 54 C relaeases 402.7 J. What will be its final temp?

leonid [27]

Data:
Q = 402.7 J → releases → Q = - 402.7 J
m = 16.25 g
T initial = 54 ºC
adopting: c = 4.184J/g/°C
ΔT (T final - T initial) = ?

Solving:

Q = m*c*ΔT
-402.7 = 16.25*4.184*ΔT
-402.7 = 67.99*ΔT
$\Delta\:T = \frac{-402.7}{67.99}$
$\boxed{\Delta\:T \approx -5.92\:^0C}$

If: ΔT (T final - T initial) = ?
$-5.92^0 = T_{final} - 54^0$
$T_{final} = 54^0 - 5.92^0$
$\boxed{\boxed{T_{final} = 48.08\:^0C}}\end{array}}\qquad\quad\checkmark$

8 0

3 years ago