Answer:
C
Explanation:
Since the car is moving at a constant speed and the street's height is not changing, there are no changes in the KE/PE levels.
Answer:
S.G = 0.79.
Explanation:
Hello there!
In this case, according to the given information in the problem, it turns out possible for us to calculate the specific gravity of this alcohol by simply dividing its density, 0.79 g/mL by that of the water, 1 g/mL just as a reference for us to work with:
![S.G=\frac{\rho _{alc}}{\rho _w}](https://tex.z-dn.net/?f=S.G%3D%5Cfrac%7B%5Crho%20_%7Balc%7D%7D%7B%5Crho%20_w%7D)
Thus, we plug in the densities to obtain:
![S.G=\frac{0.79g/mL}{1g/mL}\\\\S.G=0.79](https://tex.z-dn.net/?f=S.G%3D%5Cfrac%7B0.79g%2FmL%7D%7B1g%2FmL%7D%5C%5C%5C%5CS.G%3D0.79)
Which is dimensionless as g/mL is cancelled out due to its presence on both top and bottom of the previous formula.
Regards!
The answers alphabet is B
Animals would lose their habitat, pollution would increase in the area and the surrounding ground would become dirtier due to fluids from vehicles.