Spontaneous = exothermic. If it is not spontaneous, it is endothermic. ΔG > 0, which means that the reaction uses energy instead of emitting it.
Answer:
I don't even know I'm sorry
Answer:
The answer to your question is E = 419.435 J
Explanation:
Data
Mass = m = 2.004 g
Temperature 1 = T1 = 89°C
Temperature 2 = T2 = 139°C
Specific heat of water = Cp = 4.186 J/g°C
Energy = E = ?
Formula
E = mCp(T2 - T1)
Substitution
E = (2.004)(4.186)(139 - 89)
Simplification and result
E = 8.3887(50)
E = 419.435 J
To solve this problem, we establish the general energy balance:
ΔE = ΔU + ΔKE + ΔPE
ΔE = Q + W
Q + W = ΔU + ΔKE + ΔPE
In this case, ΔKE and ΔPE are both zero or negligible.
Given:
m = 33.0 grams of CO2
Tsub = 77 K
P = 1 atm
ΔE = Q + W
ΔE = mCpΔT + ΔPV
solve for mCpΔT, find the value of Cp for CO2, then solve for Q. Next, solve for W using the ideal gas law. Add the two values and that will be the value of the delta E.
