We conclude that Jeremy walked 2.37km North and 0.59 km West.
<h3>
How to get the North and West components?</h3>
We can assume that the distance that he walked is the hypotenuse of a right triangle, like the one you can see in the image below.
There, you can see that the adjacent cathetus would be the displacement in the North direction, while the opposite cathetus would be the displacement in the West direction.
Then we can use the relations.
- Sin(θ) = (opposite cathetus)/(hypotenuse)
- Cos(θ) = (adacent cathetus)/(hypotenuse).
With θ = 13.9° and hypotenuse = 2.44km
Solving these two we will get:
sin(13.9°) = Y/2.44km
sin(13.9°)*2.44km = Y = 0.59 km
cos(13.9°) = X/2.44km
cos(13.9°)*2.44km = X = 2.37km
So we can conclude that he walked 2.37km North and 0.59 km West.
If you want to learn more about right triangles, you can read:
brainly.com/question/2217700
Well, you haven't given us much of a choice of graphs to pick from, have you.
If a sample of an ideal gas is held at constant temperature, then
its pressure and volume are inversely proportional ... the harder
you squeeze it, the smaller the volume gets, and less squeeze
produces more volume.
Actually, the product of (pressure) x (volume) is always the
same number.
The graph of that relationship is all in the first quadrant.
It starts out very high right next to the y-axis, then drops down
toward the x-axis while curving to the right and becoming horizontal,
and ends up trying to get closer and closer to the x-axis but never
actually becoming zero.
The other bulbs will go out as well because the connection between the energy source was broken until fixed they won’t work
Answer:
Explanation:
The magnitude of the magnetic force on the proton is given by:
where:
is the proton charge
is the proton velocity
is the magnetic field
is the angle between the direction of v and B
Substituting into the formula, we find
Velocity =
(displacement)/(time for the displacement), in the direction of the displacement.
Displacement = 8 m south
Time for the displacement = 4 seconds
Direction of the displacement = south
Velocity (8 m south) / (4 seconds), to the south
Velocity = 2 m/s, toward the south
