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3 years ago

(X+h)^3 + (x+h)-(x^3+x)

1 answer:

8 0

$\dfrac{(x+h)^3 + (x+h)-(x^3+x)}{h}=\\
\dfrac{x^3+3x^2h+3xh^2+h^3+x+h-x^3-x}{h}=\\
\dfrac{3x^2h+3xh^2+h^3+h}{h}=\\3x^2+3xh+h^2+1$

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Given: m∠AOC = 120°, m∠BOD = 150°. Find: m∠BOC.

Molodets [167]

angleBOC = 270°

All 3 angles meet at O thus

angleBOC = angle AOC + angle BOD = 120° + 150° = 270°

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3 years ago

10² = ? What is 10² = to? Thanks in advance. :P

romanna [79]

To answer this exponent we will multiply the base by the power. Lets do it:-

10 = base
2 = power

10² = 10 × 10 = 100
10² = 100

CHECK OUR WORK:-

√100 = 10

We were RIGHT!!!

So, 10² = 100.

Hope i helped ya!! :)

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3 years ago

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ANSWER THIS FOR BRAINLIST If my food bill is $13.83 and I left a 2 dollar tip and also payed with a 20 dollar bill how much chan

borishaifa [10]

Answer:

$$$$4.17

Step-by-step explanation:

20-13.83=6,17

6.17-2=4.17

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3 years ago

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Eight less than the product of eleven and a number is negative nineteen. Find the number

likoan [24]

Answer:

-217 is the answer.

Step-by-step explanation:

negative nineteen is -19

eleven = 11

and from their product we have to subtract 8.

so,

-19×11

= -209

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3 years ago

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(-b3+ 3b2 + 8) - (? - 5b2 - 9) = 5b3 + 8b2 + 17 ? = DONE

zhuklara [117]

Let's solve for x.

−b3+3b2+8−(x−5b2−9)=5b3+8b2+17

Step 1: Add b^3 to both sides.

−b3+8b2−x+17+b3=5b3+8b2+17+b3

8b2−x+17=6b3+8b2+17

Step 2: Add -8b^2 to both sides.

8b2−x+17+−8b2=6b3+8b2+17+−8b2

−x+17=6b3+17

Step 3: Add -17 to both sides.

−x+17+−17=6b3+17+−17

−x=6b3

Step 4: Divide both sides by -1.

−x

−1

6b3

−1

x=−6b3

Answer:

x=−6b3

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4 years ago

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