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3 years ago

(X+h)^3 + (x+h)-(x^3+x)

1 answer:

8 0

$\dfrac{(x+h)^3 + (x+h)-(x^3+x)}{h}=\\
\dfrac{x^3+3x^2h+3xh^2+h^3+x+h-x^3-x}{h}=\\
\dfrac{3x^2h+3xh^2+h^3+h}{h}=\\3x^2+3xh+h^2+1$

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The extensions of the legs AB and CD of a trapezoid ABCD intersect at point E. Find the lengths of the sides of △AED if AB=5cm,

Lynna [10]

Answer:

AE = 15 cm; ED = 18 cm; AD = 15 cm (given)

Step-by-step explanation:

ΔBEC ~ ΔAED so ...

AD/BC = AE/BE = (BE+AB)/BE = 1 + AB/BE

Substituting given numbers (lengths in centimeters), we have ...

15/10 = 1 + 5/BE

1/2 = 5/BE

BE = 10

Similarly, ...

1/2 = 6/CE

CE = 12

Then the unknown sides are ...

AE = AB + BE = 5 + 10 = 15 . . . cm

ED = CE + CD = 12 + 6 = 18 . . . cm

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3 years ago

Based on the given segment lengths, determine whether the segments can form a triangle.

murzikaleks [220]

For 3 sides to form a triangle two sides added together need to be greater then the 3rd side. You need to check all 3 combinations:

1. 11.5 + 10.5 = 22, 22> 6.1

11.5 + 6.1 = 17.6 17.6 > 10.5

10.5 + 6.1 = 16.6, 16.6 > 11.5

This one can make a triangle.

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9.5 + 4.5 > 3.5

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3. 8 + 6.7 > 1

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4. Can make a triangle

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3 years ago

5x + 3 = 6x – 1<br> Solve for the solution

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Answer: x=4

Step-by-step explanation:

Subtract 6x from both sides.

5x+3−6x=6x−1−6x

−x+3=−1

Step 2: Subtract 3 from both sides.

−x+3−3=−1−3

−x=−4

Step 3: Divide both sides by -1.

−x/−1 = −4/−1

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↓ ↓

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