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3 years ago

Can someone help me on this work

Mathematics

1 answer:

finlep [7]3 years ago

3 0

Properties of rhombus:
1. All the sides are equal
2. Opposite angles are equal
3. Diagonal bisect each other at right angle.
4. Diagonal bisects the angle of the rhombus.

Hope you can solve the questions now:)

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A social media website had 350,000 followers in 2010. The number y of followers

Zolol [24]

Answer:

a) $y(t) = 350(1.02)^t$

b) 394 thousand = 394,000 people will be following the website in 2016

Step-by-step explanation:

Exponential equation for an amount:

The exponential equation for an amount after t years has the following format:

$y = y(0)(1+r)^t$

In which y(0) is the initial value and r is the growth rate, as a decimal.

A social media website had 350,000 followers in 2010. The number y of followers increases by 2% each year.

This means that: $y(0) = 350, r = 0.02$

a. Write an exponential growth function that represents the number of followers t years after 2010

In thousands:

$y(t) = 350(1 + 0.02)^t$

$y(t) = 350(1.02)^t$

b. How many people will be following the website in 2016?

2016 is 6 years after 2010, so this is y(6).

$y(6) = 350(1.02)^6 = 394.2$

Rounding to the nearest thousand:

394 thousand = 394,000 people will be following the website in 2016

5 0

3 years ago

Is 8:2 greater than 5:1? <br><br> I need someone to help me clarify if this is correct. Thanks.

kaheart [24]

Answer:

No, 8:2 = 4:1 which is less than 5:1

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

An exceptionally bright high school student has applied for two scholarships: a merit scholarship and an athletic scholarship. H

9966 [12]

Answer:

a) 0.70

b) 0.82

Step-by-step explanation:

Let M be the event that student get merit scholarship and A be the event that student get athletic scholarship.

P(M)=0.3

P(A)=0.6

P(M∩A)=0.08

P(not getting merit scholarships)=P(M')=?

P(not getting merit scholarships)=1-P(M)

P(not getting merit scholarships)=1-0.3

P(not getting merit scholarships)=0.7

The probability that student not get the merit scholarship is 70%.

P(getting at least one of two scholarships)=P(M or A)=P(M∪A)

P(getting at least one of two scholarships)=P(M)+P(A)-P(M∩A)

P(getting at least one of two scholarships)=0.3+0.6-0.08

P(getting at least one of two scholarships)=0.9-0.08

P(getting at least one of two scholarships)=0.82

The probability that student gets at least one of two scholarships is 82%.

4 0

3 years ago

Circle O, with center (x, y) passes through the points A(0, 0), B(-3, 0), and C(1, 2). Find the coordinates of the center of the

KonstantinChe [14]

Answer:

The center of the circle is

$(-\frac{3}{2},2)$

Step-by-step explanation:

Let the equation of the circle be

$x^2+y^2+2ax+2by+c=0$ , where (-a,-b) is the center of this circle.

The points lying the circle must satisfy the equation of this circle.

A(0,0)

We substitute this point to get;

$0^2+0^2+2a(0)+2b(0)+c=0$

$\implies c=0$

B(-3,0)

$(-3)^2+0^2+2a(-3)+2b(0)+c=0$

$\implies 9+0-6a+0+c=0$

$\implies -6a+c=-9$

But c=0

$\implies -6a=-9$

$\implies a=\frac{3}{2}$

C(1,2)

$1^2+2^2+2a(1)+2b(2)+c=0$

$1+4+2a+4b+c=0$

$2a+4b+c=-5$

Put the value of 'a' and 'c' to find 'b'

$2(\frac{3}{2})+4b+0=-5$

$3+4b+0=-5$

$4b=-5-3$

$4b=-8$

b=-2

Hence the center of the circle is

$(-\frac{3}{2},2)$

8 0

3 years ago

Using the binomial theorem , obtain the expansion of :

andrezito [222]

Answer:

see explanation

Step-by-step explanation:

Expand both factors and collect like term

Using Pascal' triangle with n = 6 to obtain the coefficients

1 6 15 20 15 6 1

Decreasing powers of 1 from $1^{6}$ to $1^{0}$

Increasing powers of 3x from $(3x)^{0}$ to $(3x)^{6}$

$1+3x)^{6}$

= 1. $1^{6}$ $(3x)^{0}$ + 6. $1^{5}$ $(3x)^{1}$ + 15. $1^{4}$ $(3x)^{2}$ + 20. $1^{3}$ $(3x)^{3}$ + 15.1² $(3x)^{4}$ + 6. $1^{1}$ $(3x)^{5}$ + 1. $1^{0}$ $(3x)^{6}$

= 1 + 18x + 135x² + 540x³ + 1215 $x^{4}$ + 1458 $x^{5}$ + 729 $x^{6}$

--------------------------------------------------------------------------------------

$(1-3x)^{6}$

= 1. $1^{6}$ $(-3x)^{0}$ + 6. $1^{5}$ $(-3x)^{1}$ + 15. $1^{4}$ $(-3x)^{2}$ + 20. $1^{3}$ $(-3x)^{3}$ + 15.1² $(-3x)^{4}$ + 6. $1^{1}$ $(-3x)^{5}$ + 1. $1^{0}$ $(-3x)^{6}$