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3 years ago

How would you graph this correctly onto a graph?

Mathematics

1 answer:

saw5 [17]3 years ago

8 0

Answer:

Here is how you graph your equations correctly :D

Step-by-step explanation:

Graph y > x − 2.

Use the slope-intercept form to find the slope and y-intercept.

Slope: 1

y-intercept: (0, -2)

Graph a dashed line, then shade the area above the boundary line since y is greater than x − 2 .

y > x - 2

Graphy < −4x + 2.

Use the slope-intercept form to find the slope and y-intercept.

Slope: -4

y-intercept: (0, 2)

Graph a dashed line, then shade the area below the boundary line since y is less than − 4 x + 2 .

y < -4x + 2

Plot each graph on the same coordinate system.

y > x - 2

Y < -4x + 2

I hope this helps.

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Which expression represents the number 2i4−5i3+3i2+−81‾‾‾‾√ rewritten in a+bi form?

vichka [17]

Answer:

The expression $-1+14i$ represents the number $2i^4-5i^3+3i^2+\sqrt{-81}$ rewritten in a+bi form.

Step-by-step explanation:

The value of $i$ is $i=\sqrt{-1}[tex] or [tex]i^{2}=-1[\tex].Now [tex]i^{4}$ in term of $i^{2}[\tex] can be written as, [tex]i^{4}=i^{2}\times i^{2}$

Substituting the value,

$i^{4}=\left(-1\right)\times \left(-1\right)$

Product of two negative numbers is always positive.

$\therefore i^{4}=1$

Now $i^{3}$ in term of $i^{2}[\tex] can be written as, [tex]i^{3}=i^{2}\times i$

Substituting the value,

$i^{3}=\left(-1\right)\times i$

Product of one negative and one positive numbers is always negative.

$\therefore i^{3}=-i$

Now $\sqrt{-81}$ can be written as follows,

$\sqrt{-81}=\sqrt{\left(81\right)\times\left(-1\right)}$

Applying radical multiplication rule,

$\sqrt{ab}={\sqrt{a}}\sqrt{b}$

$\sqrt{\left(81\right)\times\left(-1\right)}={\sqrt{81}}\sqrt{-1}$

Now, $\sqrt{\left(81\right)=9$ and $\sqrt{-1}}=i$

$\therefore \sqrt{\left(81\right)\times\left(-1\right)}=9i$

Now substituting the above values in given expression,

$2i^4-5i^3+3i^2+\sqrt{-81}=2\left(1\right)-5\left(-i\right)+3\left(-1\right)+9i$

Simplifying,

$2+5i-3+9i$

Collecting similar terms,

$2-3+5i+9i$

Combining similar terms,

$-1+14i$

The above expression is in the form of a+bi which is the required expression.

Hence, option number 4 is correct.

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3 years ago

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Answer:

Step-by-step explanation:

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u.v=(a1,b1).(a2,b2)

a1b1+a2b2

u.v=(8,-7).(3,−4)

(8)(3)+(-7)(−4)

24+28=52

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