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Sergeu [11.5K]
3 years ago
11

Find how many numbers bigger than 2,999 and less than 8,999 can be formed from the odd digits, if no digits can be repeated.

Mathematics
1 answer:
swat323 years ago
7 0
72 numbers can be formed this way.

Using just odd numbers, we could have numbers in the 3000s, 5000s, or 7000s that fit this criteria.

For each one of these, after the thousands digit is chosen, there are only 4 odd numbers that can be used for the hundreds digit, since no digits can repeat.  Then there are 3 numbers possible for the tens digit and 2 numbers possible for the ones digit.  This gives us 4(3)(2) = 24 possibilities for the 3000s, 5000s, and 7000s; 3(24) = 72.
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Answer:

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Step-by-step explanation:

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First we need to find the slope of the line that goes through (0, -3) and (3, -2).

Using both points, we can find the equation of the line:

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The parallel line needs to have the same slope as the line, so we can model the parallel line with the following equation:

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The parallel line goes through the point (-4, 2), so we have:

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b = 2 + (4/3)

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So the equation of the parallel line is:

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