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Readme [11.4K]
3 years ago
11

Find the values of the 30th and 90th percentiles of the data. Please show your work.

Mathematics
1 answer:
MaRussiya [10]3 years ago
6 0

Answer:

30th percentile:109

90th percentile: 188

Step-by-step explanation:

The given data set is:

129, 113, 200, 100, 105, 132, 100, 176, 146, 152

We arrange the data set in ascending order to obtain;

Array= 100,100,105,113,129,132,146,176,200

The 30th percentile is located at

(\frac{30}{100}\times 10 )} -th position, where n=10 is the number of items in the data set

This implies that the 30th percentile is at the 3rd position.

Since 3 is an integer, the 30th percentile is the average of the 3rd and 4th occurrence in the array;

This implies that the 30th percentile = \frac{105+113}{2}=\frac{218}{2}=109

The 90th percentile is located at

(\frac{90}{100}\times 10 )} -th position, where n=10 is the number of items in the data set

This implies that the 90th percentile is at the 9th position.

Since 9 is an integer, the 90th percentile is the average of the 9th and 10th occurrence in the array;

This implies that the 90th percentile = \frac{176+200}{2}=\frac{376}{2}=188

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A 90-inch length of ribbon is to be cut into three pieces. The longest piece is to be 30 inches longer than the shortest piece,
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Lets name the shortest piece a, the medium b and the longest c

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So if you place c=a+30 in the other 2 equasions you get

a + b + (a + 30) = 90 = 2a + b + 30
And
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Now if you put this 2 toghether u get
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