So Jeremy had x amount of money to begin with
he then spent $17 and was left with $75 to spend for camp so
x-17=75
add 17 to both sides
x=92
congrats, you're doing algebra
We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.
We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.
Formula for combination:

Where
represents the number of objects/people in the set and
represents the number of objects/people being chosen from the set
There are 23 people in the set and 10 people being chosen from the set


Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get

Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!
~ Padoru
Answer:
30
Step-by-step explanation:
You can use the triangle area theorem-
15x4(/2)=30
Answer:
B
Step-by-step explanation:
formula s =4*pi*r^2
s=4(3.14)(3^2)
s = 12.56(9)s= 113.04