Answer:
System has equal number of unknowns and equations.
Manipulation easily yielded expressions for 4 of the 7 unknowns.
However it seems that the remaining 3 unknowns x,y,z are not fixed by the equations. Different combinations (x0,y0,z0) seem possible without violating the system equations.
Is this possible, or did I most probably make a mistake in counting degrees of freedom?
Step-by-step explanation:
101 with a remainder of 12
Answer:
y = 3x+9
Step-by-step explanation:
We can use the slope intercept form
y = mx+b
where m is the slope and b is the y intercept
y = 3x +b
Substitute the point into the equation
6 = 3(-1) +b
6 = -3+b
Add 3 to each side
6+3 = -3+3+b
9 = b
y = 3x+9
Step-by-step explanation:
It seems here that they are asking us to solve for x
to do this we first need to factor
Since we can't factor this using the normal method we can instead do this
x^2 -4x-17=0
add 4 to both sides as it is a perfect square
x^2 - 4x + 4 = 17 +4
(x-2)^2 = sqrt 21
x-2 = ± 4.58
x -2 = 4.58 x-2 = -4.58
x= 6.58 x=-2.58
Or just say x=2+√21 or x=2−√21
