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S_A_V [24]
3 years ago
7

Mr. Evans is paid $9.20 per hour for the first 40 hours he works in a week. He is paid 1.5 times that rate for each hour he work

s after that. Last week Mr. Evans worked 42.25 hours. He says he earned more than $400 last week. Do you agree? Support your answer
Mathematics
2 answers:
marta [7]3 years ago
7 0
NO, in working 40 hrs x $9.20 he earned $ 368.00 overtime pay is $9.20+$ 4.60= $ 13.80 per hour $13,80 x 2.25 hours=$31.05 $368+ $31.05= $399.05 which is less than $400
lesantik [10]3 years ago
4 0
He worked 42.25 hours.
For the first 40 hours, he got $9.20 each hour.
40 hours times $9.20 = $368.

So how much did he get paid for the other 2.25 hours?
He is paid 1.5 times $9.20 each hour after that.
That's $13.80 an hour.
Times two hours is $27.60.

27.6 + 368 = Only $395.60!
Even if he got paid for that quarter of an hour, a quarter of $13.80 is only $3.45, which puts him at $399.05--still not more than $400.
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Answer:

V = 1436.76

Step-by-step explanation:

<u>Formula:</u>

V = 4/3πr³

<u>Given:</u>

r = 7

<u>Work:</u>

V = 4/3πr³

V = 4/3π(7³)

V = 4/3π(343)

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2 years ago
a cell phone company has a basic monthly plan of $40plus $0.45 for many minutes ised over 700. John was charged a total of $48.1
jonny [76]
Cost of month plan = $40

Cost of minutes used = $0.45 after 700 minutes

Total cost = $48.10

Let x be the total minutes used
Total cost = 40 + 0.45(x - 700)

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Form the equation and solve x
------------------------------------------------------------------
40 + 0.45(x - 700) = 48.10
40 + 0.45x - 315 = 48.10
0.45x - 275 = 48.10
0.45x = 48.10 + 275
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x = 323.10 ÷ 0.45
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Answer: John had used 718 mins this month
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In stage 2 of a rocket's takeoff, the speed of the rocket increases at a rate of 4.3% per minute. The speed of the rocket at the
Sveta_85 [38]

The correct option is:   B.  25000=5000(1.043)^t

<u><em>Explanation</em></u>

<u>The general form of growth equation</u> is:   A=P(1+r)^t , where A = final amount, P = initial amount, r = growth rate in decimal form and t = time duration

Here, the speed of the rocket at the beginning was 5,000 kilometers per hour and at the end will be 25,000 kilometers per hour. The speed increases at a rate of 4.3% per minute.

That means,  A= 25000 , P= 5000, r= 4.3\% = 0.043

Now <u>plugging these values into the above equation</u>, we will get......

25000=5000(1+0.043)^t\\ \\ 25000=5000(1.043)^t

So, the equation that could be used to determine the time for the speed of the rocket to reach 25,000 kilometers per hour will be:  25000=5000(1.043)^t

8 0
3 years ago
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