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3 years ago

13

Can someone help me wih this?

1 answer:

irinina [24]3 years ago

4 0

What grade is that?................

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Show many sandwiches will each group get? And How much will each group member receive?

marishachu [46]

There will be 6 groups so we divide 27 by 6 which equals 4.5. soo each group will be getting 4. everyone would get atleast one with 3 left over.

8 0

3 years ago

Find the volume of the figure

omeli [17]

Answer:

1920 ft^3

Step-by-step explanation:

Split it in 2.

14*8*10 and 10*10*8

14*10*8 = 1120

10*10*8 = 800

800 + 1120 = 1920

5 0

2 years ago

Please help! I will mark as brainliest IF answer is right. <3

Ksju [112]

Answer:

$y = - \frac{11}{2} x + 30 \frac{1}{2}$

or

$y = 30 \frac{1}{2} - \frac{11}{2} x$

if accepted:

$2y = - 11x + 61$

or

$2y = 61 - 11x$

8 0

2 years ago

Please help with 47-50

Tems11 [23]

Answer:

-3

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

What are the coordinates of the centroid of a triangle with vertices A(−3, 1) , B(1, 6) , and C(5, 2) ? Enter your answer in the

kirza4 [7]

<u>ANSWER</u>: The centroid is (1,3)

<u>Explanation:</u>

The centroid is the intersection of the medians of the triangle.

So we need to find the equation of any two of the medians and solve simultaneously.

Since the median is the straight line from one vertex to the midpoint of the opposite side, we find the midpoint of any two sides.

We find the midpoint of AC using the formula;

$N=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$

$N=(\frac{-3+5}{2}, \frac{1+2}{2})$

$N=(\frac{2}{2}, \frac{3}{2})$

$N=(1, \frac{3}{2})$

The equation of the median passes through $B(1,6)$ and $N=(1, \frac{3}{2})$ .

This line is parallel to the y-axis hence has equation

$x=1$ -------first median.

We also find the midpoint M of BC.

$M=(\frac{1+5}{2}, \frac{6+2}{2})$

$M=(\frac{6}{2}, \frac{8}{2})$

$M=(3, 4)$

The slope of the median, AM is

$Slope_{AM}=\frac{4-1}{3--3}$

$Slope_{AM}=\frac{3}{6}$

$Slope_{AM}=\frac{1}{2}$

The equation of the median AM is given by;

$y-y_1=m(x-x_1)$

We use the point M and the slope of AM.

$y-4=\frac{1}{2}(x-3)$

$2y-8=(x-3)$

$2y-x=-3+8$

$2y-x=5$ -------Second median

We now solve the equation of the two medians simultaneously by putting $x=1$ in to the equation of the second median.

$2y-1=5$

$2y=5+1$

$2y=6$

$y=3$

Hence the centroid has coordinates $(1,3)$

7 0

2 years ago

Read 2 more answers