Answer:
60
Step-by-step explanation:
Answer:
Problem 20)
Problem 21)
A)
The velocity function is:
The acceleration function is:
B)
Step-by-step explanation:
Problem 20)
We want to differentiate the equation:
We can take the natural log of both sides. This yields:
Since ln(aᵇ) = bln(a):
Take the derivative of both sides with respect to <em>x: </em>
<em /><em />
Implicitly differentiate the left and use the product rule on the right. Therefore:
Simplify:
Simplify and multiply both sides by <em>y: </em>
<em /><em />
Since <em>y</em> = (cos x)ˣ:
Problem 21)
We are given the position function of a particle:
A)
Recall that the velocity function is the derivative of the position function. Hence:
Differentiate:
The acceleration function is the derivative of the velocity function. Hence:
Differentiate:
B)
The position at <em>t</em> = 0 will be:
The velocity at <em>t</em> = 0 will be:
And the acceleration at <em>t</em> = 0 will be:
Answer:
so x = 20 , y = -21 , which is in quad IV
r^2= 400+441 = 841
r = √841 = 29
then cos Ø = 20/29
sec Ø = 29/20 = 1.45
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Answer:
45
Step-by-step explanation: