All categories

4 years ago

The radioisotope Phosphorus-32 is used in leukemia therapy. The half-life of this isotope is 14.26 days.

Mathematics

2 answers:

disa [49]4 years ago

8 0

B is the best answer that i can dee

Crank4 years ago

5 0

B I BELIEVE ! PLEASE LMK IF IM WRONG

You might be interested in

HELP ME ASAP........

butalik [34]

The sample at option B, {0, 2} is not a part of the sample space of a spinner when spun two times.

<h3>What is a sample space?</h3>

The set consists of all the possible outcomes of an event called sample points, which is said to be a sample space.

<h3>Calculation:</h3>

It is given that,

a spinner has 5 sections of equal area and each section is numbered from 1 to 5.

If the spinner is spun two times, then the possible outcomes are 25. They are:

{(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5)}

So, from the given options, the sample {0, 2} is not possible since there is no such a section on the spinner named 0.

Learn more about sample space here:

brainly.com/question/9773761

#SPJ1

8 0

2 years ago

Industry standards suggest that 10 percent of new vehicles require warranty service within the first year. Jones Nissan in Sumte

borishaifa [10]

Answer:

a) 0.3874

b) 0.3874

c) 0.1722

d) Mean and Standard Deviation = 0.9

Step-by-step explanation:

This is binomial distribution problem that has formula:

$P(x=r)=nCr*p^{r}*q^{n-r}$

Here p is probability of success = 10% = 0.1

q is probability of failure, that is 90% = 0.9

n is total number, which is 9, so n = 9

The probability that none requires warranty is r = 0, we substitute and find:

$P(x=r)=nCr*p^{r}*q^{n-r}\\P(x=0)=9C0*(0.1)^{0}*(0.9)^{9-0}\\P(x=0)=0.3874$

Probability that none of these vehicles requires warranty service is 0.3874

The probabilty exactly 1 needs warranty would change the value of r to 1. Now we use the same formula and get our answer:

$P(x=r)=nCr*p^{r}*q^{n-r}\\P(x=1)=9C1*(0.1)^{1}*(0.9)^{9-1}\\P(x=1)=0.3874$

This probability is also the same.

Probability that exactly one of these vehicles requires warranty is 0.3874

Here, we need to make r = 2 and put it into the formula and solve:

$P(x=r)=nCr*p^{r}*q^{n-r}\\P(x=2)=9C2*(0.1)^{2}*(0.9)^{9-2}\\P(x=2)=0.1722$

Probability that exactly two of these vehicles requires warranty is 0.1722

The formula for mean is

Mean = n * p

The formula for standard deviation is:

Standard Deviation = $\sqrt{n*p*(1-p)}$

Hence,

Mean = 9 * 0.1 = 0.9

Standard Deviation = $\sqrt{9*0.1*(1-0.1)}=0.9$

4 0

3 years ago

Given the m∠5 = 45°, find the measure of ∠8.

Serjik [45]

Answer:

If would be more helpful if ther was sometime of picture

6 0

2 years ago

Read 2 more answers

Is a number in decimal for repeated when the last digit is the number after it?

Lana71 [14]

Yes you are correct it is just the device can’t put that line above the number six and so the add seven to all those 6

4 0

3 years ago

Help me please! Math files attached!

Katarina [22]

AB/FG=AE/FG NO
AB/FG=BC/GH YES
AB/FG=GH/BC NO
AB/FG=HI/DC NO
BA/FG=JF/EA NO
BA/GF=CD/IH YES
FG/GH=JF/JI NO
GF/BA=JI/DE YES
HG/CB=GF/BA YES
HI/DC=AB/GF NO
IJ/AB=DE/FG NO
JF/AB=FG/EA NO
JF/EA=BA/GF NO
JF/EA=FG/AB NO

8 0

3 years ago