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kifflom [539]
3 years ago
12

PLEASEPLEASE HELPPPP!!! This is quadratics, and I need help and please show the steps. I’m not sure how to approach this, but I

know you’re supposed to put the two equations together.

Mathematics
1 answer:
Len [333]3 years ago
6 0
Start with the bottom equation and rearrange it so that it's a "y =" equation like so:
0 = 2x + 1 - y ->
y = 2x + 1

now since you know "y" you may substitute that equation 2x + 1 into "y" of the first given equation to be:
x^2 = (2x + 1) - 7 + 5x
then simplify
x^2 = 7x - 6 (I just put together like terms here to simplify the equation)

then you can make it to be: x^2 - 7x + 6 = 0
and there's your new and nice equation. now just solve for "x" using the quadratic formula or any other formula that you know

hope this helps
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2a+ 4b +30<br><br><br> 16 points
oee [108]

Answer:

2(a+2b+15)

Step-by-step explanation:

hope this helps!

8 0
3 years ago
3x-18 &gt;3 <br> need to solve for X
KATRIN_1 [288]

Answer:

x > 7

Step-by-step explanation:

3x-18 > 3

+18 3x-18 > 3 +18

3x > 21

x > 7

5 0
2 years ago
Read 2 more answers
PLEASE HELO ASAP WILL MARK BRAINLIEST
ss7ja [257]
A.) 1/2

B.) 3

For the first one, just plug the value of x (4) everywhere you see x in the formula.

For the second one, place 1 wherever you see f(x)

Hope this helps
6 0
3 years ago
HELP ME PLEASE I REALLY NEED THE HELP​
dedylja [7]

Answer:

Answer = 126 square inches

Step-by-step explanation:

Square area formula is Area = s^2    (replace the s with the side length)

Square area -->  Area = 4^2       Area = 16in

Parallelogram area formula is Area = h * b (replace h with height length and replace b with base length)

Parallelogram area --> Area = 3.5 * 10     Area = 35

Rectangle area formula is Area = w * h    (replace width and height)

Rectangle area --> Area = 12.5 * 6    Area = 75

Then add them all up  75 + 35 + 16 = 126 square inches

3 0
3 years ago
What's the domain and range for (×+4)-1
Sonja [21]
\bf a^{-{ n}} \implies \cfrac{1}{a^{ n}}\qquad \qquad&#10;&#10;\cfrac{1}{a^{ n}}\implies a^{-{ n}}\\&#10;---------------\\&#10;thus\\&#10;(x+4)^{-1}\implies \cfrac{1}{x+4}&#10;\\\\&#10;
\bf if\qquad \cfrac{1}{0} \implies undefined

so.. what value of "x" makes x+4 to 0?

the domain will be, all real numbers, except that value

about the range, "y" will take, whateve "x" can provide.. in this case... I think is all real numbers, except 0, because, if you give a few big values to "x", the fraction will simply have a bigger and bigger denominator, making the fraction smaller and smaller, ever approaching 0, but never getting there
7 0
3 years ago
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