Answer:
A
Step-by-step explanation:
6x-20= 118
6x= 118 + 20
6x = 138
x = 138/6
x= 23
Answer:
$7.50
Step-by-step explanation:
$42 × 3 = $126
$27 × 5 = $135
$126 + $135 = $261
$275 - $261 = $14
$14 - $6.50 = $7.50
Answer:
The volume of the cart will be 24 ft^3
Step-by-step explanation:
The first thing we need to calculate for this question is the number of boxes that fill the entire cart.
A layer of boxes consists of 8 boxes.
The cart holds a maximum of 3 layers of boxes.
So, the total number of boxes held by the cart are:
Total boxes = number of layers * boxes per layer
Total boxes = 3 * 8
Total boxes = 24
Since each box has a volume of one cubic foot, the total volume of the cart will be:
Volume of cart = number of boxes * volume of each box
Volume of cart = 24 * 1
Volume of cart = 24 ft^3
Answer:
2 hours, 150 miles
Step-by-step explanation:
The relation between time, speed, and distance can be used to solve this problem. It can work well to consider just the distance between the drivers, and the speed at which that is changing.
<h3>Separation distance</h3>
Jason got a head start of 20 miles, so that is the initial separation between the two drivers.
<h3>Closure speed</h3>
Jason is driving 10 mph faster than Britton, so is closing the initial separation gap at that rate.
<h3>Closure time</h3>
The relevant relation is ...
time = distance/speed
Then the time it takes to reduce the separation distance to zero is ...
closure time = separation distance / closure speed = 20 mi / (10 mi/h)
closure time = 2 h
Britton will catch up to Jason after 2 hours. In that time, Britton will have driven (2 h)(75 mi/h) = 150 miles.
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<em>Additional comment</em>
The attached graph shows the distance driven as a function of time from when Britton started. The distances will be equal after 2 hours, meaning the drivers are in the same place, 150 miles from their starting spot.