1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
const2013 [10]
3 years ago
5

What is the area of a rectangle with length 12 meters and width 6 meters? 0.5 m² 2 m² 36 m² 72 m²

Mathematics
1 answer:
ycow [4]3 years ago
3 0
Answer = 72m^2

12 x 6 = 72
You might be interested in
Find x<br><br> A. X = 23<br> B. X = 31<br> C. X = 62<br> D. X = 118
Scorpion4ik [409]

Answer:

A

Step-by-step explanation:

6x-20= 118

6x= 118 + 20

6x = 138

x = 138/6

x= 23

8 0
3 years ago
What is 5 5/8 + 6 1/4
dsp73
11.875 in decimal form. 
4 0
3 years ago
Read 2 more answers
Tiffinay plans to use 275 dollars. She wants to buy 3 pants for 42 each and 5 shirts for 27 dollars each she will pay taxs it wi
Zielflug [23.3K]

Answer:

$7.50

Step-by-step explanation:

$42 × 3 = $126

$27 × 5 = $135

$126 + $135 = $261

$275 - $261 = $14

$14 - $6.50 = $7.50

8 0
3 years ago
Coach Williams bought trophies for his players at the end of the season. Each trophy is packed in a cube-shaped box that has a v
Diano4ka-milaya [45]

Answer:

The volume of the cart will be 24 ft^3

Step-by-step explanation:

The first thing we need to calculate for this question is the number of boxes that fill the entire cart.

A layer of boxes consists of 8 boxes.

The cart holds a maximum of 3 layers of boxes.

So, the total number of boxes held by the cart are:

Total boxes = number of layers * boxes per layer

Total boxes = 3 * 8

Total boxes = 24

Since each box has a volume of one cubic foot, the total volume of the cart will be:

Volume of cart = number of boxes * volume of each box

Volume of cart = 24 * 1

Volume of cart = 24 ft^3

5 0
3 years ago
Jason and Britton are driving to St. George. Jason got a 20 mile head start and drove an
harina [27]

Answer:

  2 hours, 150 miles

Step-by-step explanation:

The relation between time, speed, and distance can be used to solve this problem. It can work well to consider just the distance between the drivers, and the speed at which that is changing.

<h3>Separation distance</h3>

Jason got a head start of 20 miles, so that is the initial separation between the two drivers.

<h3>Closure speed</h3>

Jason is driving 10 mph faster than Britton, so is closing the initial separation gap at that rate.

<h3>Closure time</h3>

The relevant relation is ...

  time = distance/speed

Then the time it takes to reduce the separation distance to zero is ...

  closure time = separation distance / closure speed = 20 mi / (10 mi/h)

  closure time = 2 h

Britton will catch up to Jason after 2 hours. In that time, Britton will have driven (2 h)(75 mi/h) = 150 miles.

__

<em>Additional comment</em>

The attached graph shows the distance driven as a function of time from when Britton started. The distances will be equal after 2 hours, meaning the drivers are in the same place, 150 miles from their starting spot.

3 0
1 year ago
Other questions:
  • Five times the larger of two consecutive odd integers is equal to one more than eight times the smaller​
    10·1 answer
  • What is a comparison sentence to represent 6 times7 equals 42
    7·2 answers
  • The number 16 has two square roots: 4 and
    9·2 answers
  • Dana is attaching a shelf to a wall and needs the shelf to be perpendicular to the wall. How many degrees should the shelf be re
    6·1 answer
  • Charlie is making a mosaic picture using 1 centimeter square tikes
    13·1 answer
  • NEED IN 5 MIN. PLEASEEE HELP
    6·1 answer
  • What is the smallest angle of rotational symmetry for the regular octagon?
    10·2 answers
  • A number when divided by 780 gives remainder 38 .What
    12·1 answer
  • What is the amplitude of 1-sin 2πx/3? Please explain.
    6·1 answer
  • YOU’RE GETTING A BRAINLIST IF YOU ANSWER THESE:
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!