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olga nikolaevna [1]

3 years ago

8

Find the sum and express it in simplest form. (3a2+2a)+(5a2-a-7)

1 answer:

Fofino [41]3 years ago

5 0

When you add 3a squared and 5a squared, you get 8a squared. 2a-a=a, with 7 leftover. the final answer would be 8a2 + a - 7

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Sally made a box to hold her jewlery collection. She used 42 inches of wood to build the sides of the box. If the box is 9 inche

Juliette [100K]

The length is 12, because if it's 9 inches wide it has two sides of 9 inches which is 18. Then subtract that from the intial value 42 to get 24. After, you divide 24 by 2 due to there being 2 sides of the box and 24 is the sum of both sides. Hopethis helps!

8 0

3 years ago

For f(x)=2x + 1 and g(x)= x^2 - 7, find (f + g)(x)

UkoKoshka [18]

The answer to the question

8 0

3 years ago

Read 2 more answers

∣x∣=−5<br> find an absoulute value

kati45 [8]

Answer:

5

Step-by-step explanatio

8 0

3 years ago

Read 2 more answers

What is the equation for the values in the table

devlian [24]

Step-by-step explanation:

Taking any two points through which the line passes;(-10,-3) and (-5,-1)

The equation of the line is given by

$\frac{y2 - y1}{x2 - x1} = \frac{y - y1}{x - x1}$

$=> \frac{ - 1 - ( - 3)}{ - 5 - ( - 10)} = \frac{y - ( - 3)}{x - ( - 10)} = \frac{y + 3}{x + 10}$

$=> \frac{ - 1 + 3}{ - 5 + 10} = \frac{y + 3}{x + 10}$

$=> \frac{2}{5} = \frac{y + 3}{x + 10}$

$=> 5(y + 3) = 2(x + 10)$

=> 5y+15 = 2x+20

=> 5y =2x+5

$=> y= \frac{2}{5} x + 1$

option C

8 0

3 years ago

Hospital records show that a certain surgical procedure takes on an average 111.6 minutes with a standard deviation of 2.8 minut

Arisa [49]

Answer:

At least 37.74% of the procedures takes between 97.6 and 125.6 minutes

Step-by-step explanation:

The percentage is the area of the standard normal distribution curve between the values 97.6 and 125.6

The standard normal variate of the given data is found as

$Z=\frac{X-\overline{X}}{\sigma }$

Thus for the given values Z is calculated as under

$Z_1=\frac{97.6-111.6}{2.8}=-5$

Similarly for the other value we have

$Z_2=\frac{125.6-111.6}{2.8}=5$

Thus the area between the calculated values can be found from standard normal distribution table to be 37.74%

8 0

3 years ago