Question

Captain Tiffany has a ship, the H.M.S. Khan. The ship is two furlongs from the dread pirate Omar and his merciless band of thieves.The Captain has probability of 1/2 of hitting the pirate ship. The pirate only has one good eye, so he hits the Captain's ship with probability 2/7.If both fire their cannons at the same time, what is the probability that both the pirate and the Captain hit each other's ships

Answer 1

Answer:

0.1428 is the probability that both the pirate and the Captain hit each other's ships.

Step-by-step explanation:

We are given the following in the question:

Probability of captain hitting pirate's ship =

$P(C)=\dfrac{1}{2}$

Probability of pirate hitting captain's ship =

$P(P) = \dfrac{2}{7}$

If events are independent events, we can write:

$P(A\cap B) =P(A)\times P(B)$

We have to evaluate the probability that both the pirate and the Captain hit each other's ships.

$P(C\cap P) = P(C) \times P(P)\\\\P(C\cap P) = \dfrac{1}{2}\times \dfrac{2}{7} = \dfrac{1}{7} = 0.1428$

0.1428 is the probability that both the pirate and the Captain hit each other's ships.

Answer 2

Answer:

The answer is 1/7

Step-by-step explanation: