Find three common denominator you’ll have have the multiplied of the numbers
Answer:
51.625
Step-by-step explanation:
you add them all up to get 415 then you divide by eight because there are eight numbers that you add up to get the answer 51.625
Below is a scale drawing of the town swimming pool. In the drawing, the longest side of the
pool has a length of 10 inches. Paco creates a new scale drawing of the pool. In his drawing,
the longest side of the pool has a length of 5 inches. What scale is Paco's new drawing?
Answer: 1,953,125
This is one single value and it is just a bit under 2 million.
Or more accurately, it's a bit over 1.9 million.
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Explanation:
- a = 5 = first term
- r = -5 = common ratio
Note that dividing any term by its previous term gets us the common ratio
- r = term2/term1 = -25/5 = -5
- r = term3/term2 = 125/(-5) = -5
The r value must stay the same the entire time, or else the sequence isn't geometric.
The nth term of any geometric sequence is a*(r)^(n-1). With the 'a' and 'r' values we found, we update that to 5(-5)^(n-1)
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To verify that is the correct nth term expression, plug in various values of n to compare it with the given sequence.
If we tried n = 2 for instance, then we find the 2nd term is
5(-5)^(n-1) = 5(-5)^(2-1) = -25
which matches what your teacher gave you. I'll let you verify the other terms.
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The last thing we need to do is plug in n = 9 and simplify
5(-5)^(n-1)
5(-5)^(9-1)
5(-5)^8
5(390625)
1,953,125 this is one single value (rather than 3 separate values)
B)

d)

9) I'm not really sure how to answer it, but I guess like 2.1, 2.2, 2.5, etc.,
10)


so {5, 6, 7, 8} is the answer
11) for some reason it won't let me insert a picture but put place

above 2, and then place

above 3, and then place

in between 2 and 3, but place it a little closer to three since

12) place

between 2 and three, but closer to two since

and also

and for number 13) the square root of 144 is 12, and the square root of 169 is 13, so any numbers between 12 and 13 will work.
I hope this helped and if not, message me and ill try to explain!