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xxTIMURxx [149]
3 years ago
5

An object is shot vertically upward from the ground with an initial velocity of 288 ft/sec. (a) At what rate is the velocity dec

reasing? Give units.
Mathematics
1 answer:
goblinko [34]3 years ago
6 0
The rate at which an object shot vertically upwards is degresing is the accerelation due to gravity given by g=9.8m/s^2

Therefore, Given that an object is shot vertically upward from the ground with an initial velocity of 288 ft/sec, the <span>rate at which the velocity decreasing is </span>g=9.8m/s^2.
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Example of fraction by finding common denominator example of fraction by finding common numerator
salantis [7]
Find three common denominator you’ll have have the multiplied of the numbers
4 0
4 years ago
Read 2 more answers
What’s the mean of 55,60,60,40,60,75,40,25
Mazyrski [523]

Answer:

51.625

Step-by-step explanation:

you add them all up to get 415 then you divide by eight because there are eight numbers that you add up to get the answer 51.625

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3 years ago
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Given a garden with a length of 300 feet and a width of 50 yards, what length of fencing would be needed to completely surround
Gnom [1K]

Below is a scale drawing of the town swimming pool. In the drawing, the longest side of the

pool has a length of 10 inches. Paco creates a new scale drawing of the pool. In his drawing,

the longest side of the pool has a length of 5 inches. What scale is Paco's new drawing?

8 0
3 years ago
Find the 9th term of the geometric sequence 5, -25, 125, ...
Mnenie [13.5K]

Answer:  1,953,125

This is one single value and it is just a bit under 2 million.

Or more accurately, it's a bit over 1.9 million.

===========================================================

Explanation:

  • a = 5 = first term
  • r = -5 = common ratio

Note that dividing any term by its previous term gets us the common ratio

  • r = term2/term1 = -25/5 = -5
  • r = term3/term2 = 125/(-5) = -5

The r value must stay the same the entire time, or else the sequence isn't geometric.

The nth term of any geometric sequence is a*(r)^(n-1). With the 'a' and 'r' values we found, we update that to 5(-5)^(n-1)

-----------------

To verify that is the correct nth term expression, plug in various values of n to compare it with the given sequence.

If we tried n = 2 for instance, then we find the 2nd term is

5(-5)^(n-1) = 5(-5)^(2-1) = -25

which matches what your teacher gave you. I'll let you verify the other terms.

-----------------

The last thing we need to do is plug in n = 9 and simplify

5(-5)^(n-1)

5(-5)^(9-1)

5(-5)^8

5(390625)

1,953,125  this is one single value (rather than 3 separate values)

4 0
3 years ago
Can someone please help me with b, d, and 9-13? I already drew a number line, thanks in advance! :)
inessss [21]
B)
\frac{3}{13}  = s
d)
\frac{5}{4}  = s
9) I'm not really sure how to answer it, but I guess like 2.1, 2.2, 2.5, etc.,

10)
{2}^{2}  = 4
{3}^{2}  = 9
so {5, 6, 7, 8} is the answer

11) for some reason it won't let me insert a picture but put place
\sqrt{4}
above 2, and then place
\sqrt{9}
above 3, and then place
\sqrt{7}
in between 2 and 3, but place it a little closer to three since
\sqrt{7}  = 2.65
12) place
\sqrt{5}
between 2 and three, but closer to two since
\sqrt{5}  = 2.24
and also
\sqrt{5}  <  \sqrt{7}
and for number 13) the square root of 144 is 12, and the square root of 169 is 13, so any numbers between 12 and 13 will work.


I hope this helped and if not, message me and ill try to explain!
8 0
3 years ago
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