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3 years ago

What is the equation in point slope form of the line passing through (0,5) and (-2,11)

Mathematics

1 answer:

IRISSAK [1]3 years ago

6 0

The equation of the line passing through $(x_1,y_1)$ and $(x_2,y_2)$ is

$\frac{x-x_1}{y-y_1} =\frac{x_2-x_1}{y_2-y_1}$ . Here

$\frac{y_2-y_1}{x_2-x_1}$ is the slope of the line.

Substituting numerical values, the equation of the line is

$\frac{x-0}{y-5} =\frac{-2-0}{11-5} \\ \frac{x}{y-5} =-\frac{1}{3} \\ 3x=5-y\\ 3x+y=5$

The equation of the line is $3x+y=5$

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A 100-gallon fish tank fills at a rate of x gallons per minute. The tank has already been filling for 5 minutes. The

vagabundo [1.1K]

Answer:

was shifted 5 unit right side then stretched vertically by the factor 100, Shifted 5 unit right side then stretched vertically by the factor 100

Step-by-step explanation:

Here, parent function,

Transformed function,

Since, if a function f(x) gives cf(x), where c is any number,

Then the function was vertically stretched by factor c,

While, the function gives f(x-c),

Then the function was shifted c unit right.

Hence, the graph of was shifted 5 unit right side then stretched vertically by the factor 100 to create the graph of

6 0

3 years ago

Find the nth term of the sequence:<br>23, 19, 13, 5, -5.......<br>

Maurinko [17]

Answer:

Step-by-step explanation:

Given the sequence :

23, 19, 13, 5, -5.......

From the sequence, the common difference is unequal, as their is a constant Increment in the difference after successive numbers.

19 - 23 = -4

13 - 19 = -6

5 - 13 = -8

-5 - 5= -10

Hence an constant difference of - 2 after each successive difference.

Hence, this is a quadratic sequence

With the formula

an² + bn + c

8 0

3 years ago

Can someone plz help me

Pani-rosa [81]

Answer:

I got 172.05

Step-by-step explanation:

I used a calculator on goo gle calculatorsoup.com

5 0

3 years ago

Is (2,-5) is an answer to 4+3x=-2y

bearhunter [10]

Yes. For example x=-1 and y=-1/2

4 0

3 years ago

The Resource Conservation and Recovery Act mandates the tracking and disposal of hazardous waste produced at U.S. facilities. Pr

aniked [119]

Answer:

(a) $E(X) = 0.383$

The expected number in the sample that treats hazardous waste on-site is 0.383.

(b) $P(x = 4) = 0.000169$

There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

Step-by-step explanation:

Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.

N = 209

Only eight of these facilities treated hazardous waste on-site.

r = 8

a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?

n = 10

The expected number in the sample that treats hazardous waste on-site is given by

$E(X) = \frac{n \times r}{N}$

$E(X) = \frac{10 \times 8}{209}$

$E(X) = \frac{80}{209}$

$E(X) = 0.383$

Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.

b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site

The probability is given by

$P(x = 4) = \frac{\binom{r}{x} \binom{N - r}{n - x}}{\binom{N}{n}}$

For the given case, we have

N = 209

n = 10

r = 8

x = 4

$P(x = 4) = \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}}$

$P(x = 4) = \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}}$

$$ P(x = 4) = \frac{70 \times 84944276340}{35216131179263320}$

$P(x = 4) = 0.000169$

Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

8 0

3 years ago