Question

What is the equation in point slope form of the line passing through (0,5) and (-2,11)

Answer 1

The equation of the line passing through $(x_1,y_1)$ and $(x_2,y_2)$ is

$\frac{x-x_1}{y-y_1} =\frac{x_2-x_1}{y_2-y_1}$. Here

$\frac{y_2-y_1}{x_2-x_1}$ is the slope of the line.

Substituting numerical values, the equation of the line is

$\frac{x-0}{y-5} =\frac{-2-0}{11-5} \\ \frac{x}{y-5} =-\frac{1}{3} \\ 3x=5-y\\ 3x+y=5$

The equation of the line is $3x+y=5$