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nadezda [96]
3 years ago
8

Help!! I totally forgot how to do this.

Mathematics
1 answer:
Elden [556K]3 years ago
4 0

This could be COMPLETELY wrong but

(-2, 1)

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Quadrilateral ABCD is the result of a translation of quadrilateral EFGH. Segment EF is parallel to segment HG in the pre-image.
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Translations of figures preserve the lengths and angles of the original figures, then all the segments of the image figure are parallel to correspondant segments of the original figure.

Then you can state that the same relation between any two sides of the original figure is what you will have for the image.

AB is parallel to HE

AD is parallel to HG

DC is parallel to GF

BC is parallel to EF


Then is EF is parallel to HG in the pre-image the correspondant segments in the image are parallel too, i.e. BC is parallel to AD in the image.
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