There are 21 black socks and 9 white socks. Theoretically, the probability of picking a black sock is 21/(21+9) = 21/30 = 0.70 = 70%
Assuming we select any given sock, and then put it back (or replace it with an identical copy), then we should expect about 0.70*10 = 7 black socks out of the 10 we pick from the drawer. If no replacement is made, then the expected sock count will likely be different.
The dot plot shows the data set is
{5, 5, 6, 6, 7, 7, 7, 8, 8, 8}
The middle-most value is between the first two '7's, so the median is (7+7)/2 = 14/2 = 7. This can be thought of as the average expected number of black socks to get based on this simulation. So that's why I consider it a fair number generator because it matches fairly closely with the theoretical expected number of black socks we should get. Again, this is all based on us replacing each sock after a selection is made.
<u>Given </u><u>:</u><u>-</u>
- A dealer sold a photocopy machine at Rs 4200 with 13% VAT to a retailer.
- The retailer added transportation cost of Rs 250 , profit Rs 300 and local tax Rs 150 and sold to consumer .
- Customer has to pay 13% VAT .
<u>To </u><u>Find </u><u>:</u><u>-</u>
- Amount to be paid by the customer .
<u>Sol</u><u>u</u><u>tion </u><u>:</u><u>-</u>
Here , according to the question ,
Therefore cost after adding VAT ,
Again the values added by the retailer before selling to customer ,
- Transport = Rs 250
- Profit = Rs 300
- Tax = Rs 150
Therefore total cost after adding these ,
Again Selling price after addition of 13% VAT ,
<u>Hence </u><u>the </u><u>amount </u><u>to </u><u>be </u><u>paid </u><u>by </u><u>the </u><u>customer </u><u>is </u><u>Rs </u><u>6</u><u>1</u><u>5</u><u>4</u><u> </u><u>.</u>
Answer:
= 
Step-by-step explanation:
When dividing values with exponents, we simply need to subtract the numerators exponent to the denominators exponent.
So we have:
= 
= 
Now since we have a negative exponent, we can get the reciprocal of the value to make it positive.
= 