ann is grouping 38 rocks, she can put into groups of 10 rocks or as single rocks what are the different ways she can group them

1 answer:

5 0

Since Anna is either grouping them as single rock or as group of 10, we need to find the maximum number of groups of 10 as follows: 38/10 = 3.8

This means that Anna can make maximum 3 groups of 10 rocks.

Based on this, the different ways to group the rocks are as follows:
- 3 groups of 10 and 8 (which are calculated as: 38-30) single rocks
- 2 groups of 10 and 18 (which are calculated as: 38-20) single rocks
- 1 group of 10 and 28 (which are calculated as: 38-10) single rocks
- 0 group of 10 and 38 (which are calculated as: 38-0) single rocks

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Two cards are selected from a standard deck of 52 playing cards. The first card is not replaced before the second card is select

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Answer:

Probability is: $\frac{\textbf{13}}{\textbf{51}}$

Step-by-step explanation:

From a deck of 52 cards there are 26 black cards. (Spades and Clubs).

Also, there are 26 red cards. (Hearts and Diamonds).

First, we determine the probability of drawing a black card.

P(drawing a black card) = $\frac{number \hspace{1mm} of \hspace{1mm} black \hspace{1mm} cards}{total \hspace{1mm} number \hspace{1mm} of \hspace{1mm} cards}$ $= \frac{26}{52} = \frac{\textbf{1}}{\textbf{2}}$

Now, since we don't replace the drawn card, there are only 51 cards.

But the number of red cards is still 26,

∴ P(drawing a red card) = $\frac{number \hspace{1mm} of \hspace{1mm} red \hspace{1mm} cards}{total \hspace{1mm} number \hspace{1mm}of \hspace{1mm} cards}$ $= \frac{26}{51}$