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8_murik_8 [283]
3 years ago
8

Which expression represents 23 multiplied by the sum of 3 and 5 divided by 6

Mathematics
2 answers:
LenKa [72]3 years ago
5 0
23x(3+5)/6 is the answer
ZanzabumX [31]3 years ago
3 0

Answer:

<em>i will give you the expression but can you post the choices</em>

Step-by-step explanation:

  • <em>23(3 + 5) / 6</em>
  • <em>so we would do 23 x 5 + 3 which is 8 we just simplified this expression</em>
  • <em>Then after that i would do 23 x 8 which is 184</em>
  • <em>Last we would do 184/6 = 30.66......</em>
  • <em>I would round that and i get 30.6</em>

<em></em>

<em></em>

<em></em>

  • <em>Hope this helps</em>
  • <em>Hope this is right</em>
  • <em>Brainliest plz</em>
  • <em>If you need the answer to this expression I gave it to you</em>
  • <em>Hope I didn't do extra </em>
  • <em>Ask me questions</em>

<em></em>

<em></em>

<em></em>

<em></em>

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crimeas [40]

Answer:

The zeros are:

x =4, x=2, x = 5

  • The function has three distinct real zeros.

Hence, option (B) is true.

Step-by-step explanation:

Given the expression

h\left(x\right)=\left(x-4\right)^2\left(x^2-7x+\:10\right)

Let us determine the zeros of the function by putting h(x) = 0 and solving the expression

0=\left(x-4\right)^2\left(x^2-7x+10\right)

switch sides

\left(x-4\right)^2\left(x^2-7x+10\right)=0

as

x^2-7x+\:10=\left(x-2\right)\left(x-5\right)

so

\left(x-4\right)^2\left(x-2\right)\left(x-5\right)=0

Using the zero factor principle

  • \mathrm{If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

so

x-4=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x =4, x=2, x = 5

Thus, the zeros are:

x =4, x=2, x = 5

It is clear that there are three zeros and all the zeros are distinct real numbers.

Therefore,

  • The function has three distinct real zeros.

Hence, option (B) is true.

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spayn [35]

<u>Answer:</u>

The correct answer option is \frac { 4 } { 4 9 }.

<u>Step-by-step explanation:</u>

We are to find the probability that both your parents were born on weekend (either Saturday or Sunday).

Total number of days in a week = 7

Number of days in weekend = 2

Probability of being born on weekend = \frac { 2 } { 7 }

P (both parents were born on weekend) = \frac{2}{7} \times \frac{2}{7} = 4/49

3 0
3 years ago
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