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kozerog [31]
3 years ago
15

dawn has 5/6 yard of lace. She uses 4/5 of it for a dress and the rest for a jewel box. How much lace does she use for the jewel

box.
Mathematics
2 answers:
Brums [2.3K]3 years ago
6 0
5/6 x 4/5= 20/30 ----->2/3 Used for dress
5/6 -2/3= amount used for jewel box ---> 1/6 yard
GrogVix [38]3 years ago
3 0
amount\ used\ for\ jewel\ box=all\ lace-\ lace\ used\ for\ dress\\\\\
amount\ used\ for\ jewel\ box=\frac{5}{6}-\frac{4}{5}=\frac{25}{30}-\frac{24}{30}=\frac{1}{30}\\\\ \frac{1}{30}\ of\ lace\ is\ for\ jewel\ box.

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Instructions:Select the correct answer.
aivan3 [116]
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4 8 12 16

also each time it goes up the price increases by two 

Hope this helped

(if you dont want to read all that the answer is 18)



3 0
3 years ago
AP Calculus redo! I know the answer but can't figure out exactly how to get there. Thank you! I want to work through the steps.
Monica [59]
You're approximating

\displaystyle\int_1^5 x^2\,\mathrm dx

with a Riemann sum, which comes in the form

\displaystyle\int_a^b f(x)\,\mathrm dx=\lim_{n\to\infty}\sum_{i=1}^nf(x_i)\Delta x_i

where x_i are sample points chosen according to some decided-upon rule, and \Delta x_i is the distance between adjacent sample points in the interval.

The simplest way of approximating the definite integral is by partitioning the interval into equally-spaced subintervals, in which case \Delta x=\dfrac{b-a}n, and since [a,b]=[1,5], we have

\Delta x=\dfrac{5-1}n=\dfrac4n

Using the right-endpoint method, we approximate the area under f(x) with rectangles whose heights are determined by their right endpoints. These endpoints are chosen by successively adding the subinterval length to the starting point of the interval of integration.

So if we had n=4 subintervals, we'd split up the interval of integration as

[1,5]=[1,2]\cup[2,3]\cup[3,4]\cup[4,5]

Note that the right endpoints follow a precise pattern of

2=1+\dfrac44
3=1+\dfrac84
4=1+\dfrac{12}4
5=1+\dfrac{16}4

The height of each rectangle is then given by the values above getting squared (since f(x)=x^2). So continuing with the example of n=4, the Riemann sum would be

\displaystyle\sum_{i=1}^4\left(1+\dfrac{4i}4\right)^2\dfrac44

For n=5,

\displaystyle\sum_{i=1}^5\left(1+\dfrac{4i}5\right)^2\dfrac45

and so on, so that the definite integral is given exactly by the infinite sum

\displaystyle\lim_{n\to\infty}\sum_{i=1}^n\left(1+\dfrac{4i}n\right)^2\dfrac4n
4 0
3 years ago
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Rom4ik [11]

Answer:

A.) Paul

B.) Plain

C.) Paul

Step-by-step explanation:

Paul: Shirt - Striped; Jumper - Spotted; Towel - Plain

Kerry: Shirt - Plain; Jumper - Striped; Towel - Spotted

Sandra: Shirt - Spotted; Jumper - Plain; Towel - Striped

Hope this helps! Have a nice dayy! :)

6 0
3 years ago
If the timer was started at the begining if the race would it affect the median. Why, not?
Ilia_Sergeevich [38]
Yeah It Would

~Hope This Helps :)
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lisov135 [29]

Answer:

50 days

Step-by-step explanation:

2500/50 = 50

Answer: 50 days

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