Answer:
What is the probability that a randomly selected family owns a cat? 34%
What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat? 82.4%
Step-by-step explanation: We can use a Venn (attached) diagram to describe this situation:
Imagine a community of 100 families (we can assum a number, because in the end, it does not matter)
So, 30% of the families own a dog = .30*100 = 30
20% of the families that own a dog also own a cat = 0.2*30 = 6
34% of all the families own a cat = 0.34*100 = 34
Dogs and cats: 6
Only dogs: 30 - 6 = 24
Only cats: 34 - 6 = 28
Not cat and dogs: 24+6+28 = 58; 100 - 58 = 42
What is the probability that a randomly selected family owns a cat?
34/100 = 34%
What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?
A = doesn't own a dog
B = owns a cat
P(A|B) = P(A∩B)/P(B) = 28/34 = 82.4%
<span>47184.
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<span>Así que la suma de los cientos y miles será dos veces el dígito de las unidades . Miles ( 7 ) + cientos ( 1 ) = 8. 8 es dos veces más que el dígito de las unidades ( 4) de los miles de diez dígitos es el mismo que el de un dígito es así, esto hace que los miles a decenas 4 también .
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(No escribo bien en espanol pero te lo traslatide jaja. dame un messaje si no todavia no entiendes)
Answer:
Step-by-step explanation:
(times 6 on both sides)
(add 4 to both sides)
(divide R on both sides)
thus
Answer:
57cm²
Step-by-step explanation:
area for trapezoid=
b¹+b²=x
x÷2=v
v×h=z
h=height
b=base
14+5=19
19÷2=9.5
9.5×6=57
Step-by-step explanation:
what number you need help with