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Naddik [55]
3 years ago
14

Can someone please explain to me how to do this

Mathematics
1 answer:
nasty-shy [4]3 years ago
6 0
You plug in the x’s to the equation up top to gin the y
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Algerabuc equation<br> 3x + 5 = 14
dexar [7]

Answer: x=3

Step-by-step explanation:

3x + 5 = 14

Subtract 5 from both sides

3x=9

Divide both sides by 3 to get x alone

x=3

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3 years ago
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What is the answer for number 12
GalinKa [24]
(3*4)+(1*7)/7*4 = 12+7/28 = 19/28

your answer is 19/28
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mihalych1998 [28]

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ANTONII [103]

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Step-by-step explanation:

6 0
3 years ago
Evaluate the integral of the quotient of the cosine of x and the square root of the quantity 1 plus sine x, dx.
VMariaS [17]

Answer:

∫((cos(x)*dx)/(√(1+sin(x)))) = 2√(1 + sin(x)) + c.

Step-by-step explanation:

In order to solve this question, it is important to notice that the derivative of the expression (1 + sin(x)) is present in the numerator, which is cos(x). This means that the question can be solved using the u-substitution method.

Let u = 1 + sin(x).

This means du/dx = cos(x). This implies dx = du/cos(x).

Substitute u = 1 + sin(x) and dx = du/cos(x) in the integral.

∫((cos(x)*dx)/(√(1+sin(x)))) = ∫((cos(x)*du)/(cos(x)*√(u))) = ∫((du)/(√(u)))

= ∫(u^(-1/2) * du). Integrating:

(u^(-1/2+1))/(-1/2+1) + c = (u^(1/2))/(1/2) + c = 2u^(1/2) + c = 2√u + c.

Put u = 1 + sin(x). Therefore, 2√(1 + sin(x)) + c. Therefore:

∫((cos(x)*dx)/(√(1+sin(x)))) = 2√(1 + sin(x)) + c!!!

4 0
3 years ago
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