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xz_007 [3.2K]
3 years ago
13

Work out the volume of a cuboid 5cm by 3cm by 6cm?

Mathematics
1 answer:
Ainat [17]3 years ago
3 0
To calculate the area just multiply all the sides together so it's 5x3x6 and the answer is 90
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Evaluate t-u/v, when t=-1,u=-3 and v=1/2
mars1129 [50]

Answer:

5

Step-by-step explanation:

t-u/v

substitute (-1) - (-3)/(1/2)

divide     (-1) - (-6)

simplify   (-1) + 6

add         5

3 0
3 years ago
- Which fraction has a value that's equal to 3/4?<br> A. 4/3<br> ) B. 12/12<br> c. ²6<br> D. 12/16
yaroslaw [1]
12/16
If you divide 12 by 4 you get 3 and if you divide 16 by 4 you get 4 so that would be 3/4
7 0
3 years ago
Read 2 more answers
Which fraction is equivalent to : 3/8 +1/8
Crank
1/2 because you can simplify 4/8 and do 4 divided by 4 and 8 divided by 4 which is 1/2
7 0
3 years ago
Read 2 more answers
Please help
Harman [31]

Answer:

we get \mathbf{gf(2)=-\frac{1}{3}}

Step-by-step explanation:

We are given:

f(x)=1-2x\\g(x)= \frac{1}{x}\\h(x)=x^3+1

We need to find value of gf(2)

gf(2)=g(f(2))

First putting f(x) inside of g(x) and then putting x=2

gf(x)=g(f(x))\\gf(x)=\frac{1}{1-2x}

Now putting x=2 to find gf(2)

gf(x)=\frac{1}{1-2x}\\gf(2)=\frac{1}{1-2(2)}\\gf(2)=\frac{1}{1-4}\\gf(2)=\frac{1}{-3}\\gf(2)=-\frac{1}{3}

So, we get \mathbf{gf(2)=-\frac{1}{3}}

3 0
3 years ago
What is the probability that a randomly selected permutation of the letters A, A, C, C, L, L, O, R, T, U would spell "calculator
kirill [66]

Answer:

See explanation

Step-by-step explanation:

Total number of letters = n! = 10

Permutation for 10 letters = n!

                                          = 10!

                                          = 10*9*8*7*6*5*4*3*2*1

                                          = 3628800

From n letters:

Number of A = 2

Number of C = 2

Number of  L = 2

A₁, A₂, C₁, C₂, L₁, L₂, O, R, T, U

Out of 3628800 permutations the word calculator can be spelled as:

C₁ A₁ L₁ C₂ U L₂ A₂ T O R

C₂ A₂ L₂ C₁ U L₁ A₁ T O R

and so on

So total number of different permutations are  

(permutation of number of letters) / permutation of (number of As * number of Cs * number of Ls)

  =  10! / (2! 2! 2 !)  

  = 10*9*8*7*6*5*4*3*2*1 / (2*1) (2*1) (2*1)

  = 3628800 / 2 * 2 * 2

  =  3628800 / 8

  =   453600

Hence probability that a randomly selected permutation of the letters A, A, C, C, L, L, O, R, T, U would spell "calculator" is:

 1 / total number of different permutations  

= 1 / 10! / (2! 2! 2 !)  

= 1/453600

= 0.000002

8 0
3 years ago
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