Question

How do you Graph y-3=1/3(x+1)

Answer 1

Answer:

You can find the point of intersection of the line with the y-axis and the  the point of intersection of the line with the x-axis. See the graph attached.

Step-by-step explanation:

Find the intersection with the y-axis. Substitute $x=0$ into the equation and solve for y:

$y-3=\frac{1}{3}(x+1)\\\\y-3=\frac{1}{3}(0+1)\\\\y-3=\frac{1}{3}(1)\\y=\frac{1}{3}+3\\\\y=\frac{10}{3}$

$y$≈3.33

Find the intersection with the x-axis. Substitute $y=0$ into the equation and solve for x:

$y-3=\frac{1}{3}(x+1)$

$0-3=\frac{1}{3}(x+1)\\(-3)(3)=x+1\\-9-1=x\\x=-10$

Now, you know that the line passes through the point (0,3.33) and (-10,0). Now you can graph the function. (Observe the graph attached)