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3 years ago

If 98 is a composite or prime

Mathematics

2 answers:

Marina86 [1]3 years ago

7 0

98 isnt a prime, which means that it is a composite number

jek_recluse [69]3 years ago

7 0

Answer:98 is not prime so it is a composite

Step-by-step explanation:

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Rewrite the expression with rational exponents as a radical expression.

nexus9112 [7]

Answer:

If the expression is $4x^\frac{3}{7}$ , then the answer is the first option.

If the expression is $(4x)^\frac{3}{7}$ , then the answer is the third option.

Step-by-step explanation:

Remember that when you have a radical expression in the form $\sqrt[n]{x}$ , you can rewrite as:

$=x^\frac{1}{n}$

Then:

- If the expression is $4x^\frac{3}{7}$ , then you can rewrite it in the following radical form:

$=4\sqrt[7]{x^3}$ (This form matches with the first option.)

- If the expression is $(4x)^\frac{3}{7}$ , then you can rewrite it in the following radical form:

$=\sqrt[7]{(4x)^3}$ (This form matches with the third option).

7 0

3 years ago

Read 2 more answers

Am I doing this right!

Leni [432]

16 thru 23 look wrong and 16 is absolutely wrong. You use this:https://www.mathpapa.com/algebra-calculator.html to work out the answers and it shows the steps and explains it to you better than I could. Good luck

4 0

3 years ago

If the perimeter is 168 and the width is 6 feet longer than thr length what are the dimensions

Ksenya-84 [330]

$\bf \textit{perimeter of a rectangle}\\\\ P=2(L+w)~~ \begin{cases} L=length\\ w=width\\ ----------\\ P=168\\ w=\stackrel{\textit{6 feet longer than L}}{L+6} \end{cases}\implies 168=2(L+\stackrel{w}{L+6}) \\\\\\ 84=2L+6\implies 78=2L\implies \cfrac{78}{2}=L\implies \boxed{39=L} \\\\\\ w=39+6\implies \boxed{w=45}$

4 0

3 years ago

Which statements about the hyperbola are true? Check all that apply. A. There is a focus at (0,−10). B. There is a focus at (0,

hichkok12 [17]

Answer:

A. There is a focus at (0,−10).

Step-by-step explanation:

Assume the hyperbola is like the one below.

The hyperbola is vertical and centred on the y-axis, so its general equation is

$\dfrac{y^{2}}{a^{2}} - \dfrac{x^{2}}{b^{2}} = 1$

The vertices of your parabola are (0,±8) so a = 8.

The covertices are (±6,0), so b = 6.

Calculate c

$\begin{array}{rcl}a^{2} + b^{2} & = & c^{2}\\8^{2} + 6^{2} & = & c^{2}\\64 + 36 & = & c^{2}\\100 & = & c^{2}\\c & = & \mathbf{10}\\\end{array}$

A. Foci

The foci are at (0, ±c) = (0, ±10)

TRUE. There is a focus at (0,-10).

B. Foci

The foci are at (0,±10).

False. There is no focus at (0,12)

C. and D. Asymptotes

The equations for the asymptotes are

$y = \pm\dfrac{a}{b}x = \pm\dfrac{8}{6}x = \pm\dfrac{4}{3}x$

So, y = ±x are not asymptotes.

False.

E. and F. Directrices

The equations of the directrices are

y = ±a²/c = ±64/10 = ±6.4

y = 6.4 is a directrix.

E is false. x = cannot be a directrix

F is uncertain. Your equation for the directrix is incomplete.

3 0

4 years ago

Stephanie surveyed the students in her class to find out their favorite color. her results are in the table. what percent of ste

viktelen [127]

You have to add them all together to get 25. 16 students did not say blue, so you have to divide 16 by 25. 64% did not choose blue

4 0

3 years ago