This question is worth 10 points pls help
1 answer:
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Answer:
Probability that a smoker has lung disease = 0.2132
Step-by-step explanation:
Let L = event that % of population having lung disease, P(L) = 0.07
So,% of population not having lung disease, P(L') = 1 - P(L) = 1 - 0.07 = 0.93
S = event that person is smoker
% of population that are smokers given they are having lung disease, P(S/L) = 0.90
% of population that are smokers given they are not having lung disease, P(S/L') = 0.25
We know that, conditional probability formula is given by;
P(S/L) =
= P(S/L) * P(L)
= 0.90 * 0.07 = 0.063
So, = 0.063 .
Now, probability that a smoker has lung disease is given by = P(L/S)
P(L/S) =
P(S) = P(S/L) * P(L) + P(S/L') * P(L')
= 0.90 * 0.07 + 0.25 * 0.93 = 0.2955
Therefore, P(L/S) = = 0.2132
Hence, probability that a smoker has lung disease is 0.2132 .
Answer:
Yes, The analysis involves a statistical test.
The hypothesis are
Step-by-step explanation:
Consider the provided information.
Testing 500 right-handed participants on the reaction time of their left and right hands to determine if there is evidence for the claim that the right hand reacts faster than the left.
Yes, The above analysis involves a statistical test.
Where claim is right hand reacts faster than the left hand.
If right hand reacts faster that means the reaction time of right hand should be smaller than the reaction time of left hand.
Let to be the average reaction time of their right hands for the right-handed participants and
to be the average reaction time of their left hands.
Therefore, the hypothesis are