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hram777 [196]
3 years ago
8

Daniel earns a commission of 3% on every home he sells. Recently, Daniel

Mathematics
1 answer:
Leokris [45]3 years ago
7 0

Answer:

The answer in 180000 * 3 ÷ 100 = 5400$

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What is the solution to the equation 1.6m − 4.8 = −1.6m?
nordsb [41]
See attached picture for answre

7 0
2 years ago
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Which expressions are equivalent to (2^2-9) (x + 3)?
mestny [16]

Answer:

(x^2-3^2)(x+3)

(x-3)(x+3)(x+3)

(x-3)(x+3)^2

Step-by-step explanation:

Given

(x^2-9)(x+3)

Required

Select 3 equivalent expressions

(x^2-9)(x+3)

Express 9 as 3^2

(x^2-3^2)(x+3) --- This is one equivalent expression

Take x^2 - 3^2 as difference of two squares

(x-3)(x+3)(x+3) -- This is another equivalent expression:

Solving further:

(x-3)(x+3)(x+3) becomes

(x-3)(x+3)^2   -- This is another equivalent expression:

Hence, the equivalent expressions are:

(x^2-3^2)(x+3)

(x-3)(x+3)(x+3)

(x-3)(x+3)^2

7 0
2 years ago
15. Using the circle below, find each arc length. Round to the nearest hundredth. R a) ST b) RPT 97 125 PS = 28 feet
Troyanec [42]

The measure of arcPR and arcRPT are 83 and 208 degrees respectively

The measure of arc ST will be gotten using the expression below:

arcPS = arcPT + arcST

Given the following

  • arcPT = 125 degrees
  • arc PS = 180 degrees

arcST = arcPS - arcPT

arcST = 180  - 125

arcST = 55 degrees

Similarly, arcPR = 180 - arcRS

arcPR = 180 - 97

arcPR = 83 degrees

arcRPT = arcPR + arcPT

arcRPT = 83 + 125

arcRPT = 208 degrees

Hence the measure of arcPR and arcRPT are 83 and 208 degrees respectively

Learn more about circles here: brainly.com/question/24375372

7 0
2 years ago
FIND AC! PLS HELP!!
Anna007 [38]

Answer:

AC = 7.3 in

Step-by-step explanation:

tan(51°) = 9/AC

1.24 = 9/AC

AC = 9/1.24

AC = 7.26

5 0
2 years ago
Find the side in of point a to point c
vladimir1956 [14]

Step 1:

Calculate the measure of angle ∠ABC

\angle DBC+\angle ABC=180(\text{ sum of angles on a straight line)}\angle ABC=65^0\begin{gathered} \angle DBC+\angle ABC=180 \\ \angle DBC+65^0=180^0 \\ \angle DBC=180^0-65^0 \\ \angle DBC=115^0 \end{gathered}

From the triangle in the question,

a=10\operatorname{km},c=15\operatorname{km},B=115^0

Step 2:

Calculate the value of AB using the cosine rule below

b^2=a^2+c^2-2\times a\times c\times\cos B

By substituting the values, we will have

\begin{gathered} b^2=a^2+c^2-2\times a\times c\times\cos B \\ b^2=10^2+15^2-2\times10\times15\times\cos 115^0 \\ b^2=100+225-300\times(-0.4226) \\ b^2=325+126.78 \\ b^2=451.78 \\ \text{Square root both sides} \\ \sqrt[]{b^2}=\sqrt[]{451.78} \\ b=21.26\operatorname{km} \end{gathered}

Hence,

The distance of point A to point C is = 21.26km

3 0
9 months ago
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