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4 years ago

HELP PLEASE!!!!

Mathematics

2 answers:

iris [78.8K]4 years ago

4 0

Answer:

1: a,b, correct order of the triangle points

2: d

pochemuha4 years ago

3 0

Answer:

Not sure about the first one.

For the second question: d. reflect over x-axis, reflect over y-axis, then translate 2 units up

Step-by-step explanation:

It is reflected over both axis and then moved up 2 units.

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Which of the following theorems verifies that triangle STU is congruent to triangle XYZ

Leni [432]

Answer:

B. HL

Step-by-step explanation:

4 0

3 years ago

HURRY!!! How is completing the square beneficial? (in quadratic equation)

givi [52]

"Completing the square" is a step in the solution of quadratic equations. It can be accomplished without the guesswork or trial-and-error associated with methods like factoring, and it always leads to a solution. It is the method by which the quadratic formula is derived.

7 0

3 years ago

Y = -2x2 + 10 y = -2x – 2

34kurt

Answer:

x = 6

y = - 14

Step-by-step explanation:

$\left \{y=-2x2 + 10y} \atop {y=-2x -2}} \right.$

-2x × 2 + 10 = - 2x - 2
x = 6
y = -2 × 6 - 2 = - 14

4 0

3 years ago

Read 2 more answers

What is the common ratio of 2, 10/3, 50/9

mojhsa [17]

The common ratio of 2, 10/3, 50/9 is $\frac{10}{6}$

Solution:

Given, series of elements are $2, \frac{10}{3}, \frac{50}{9}$

We have to find the common ratio of the above given series.

We know that, common ratio of an G.P is division of any number in that series with the previous number of the series.

So, now take $\frac{10}{3}$ and 2

$\text { Then, common ratio }=\frac{\frac{10}{3}}{2}$

$\begin{array}{l}{\text { Common ratio }=\frac{10}{3} \times \frac{1}{2}} \\\\ {\text { Common ratio }=\frac{10}{3 \times 2}=\frac{10}{6}}\end{array}$

Hence, the common ratio of the given series is $\frac{10}{6}$

6 0

3 years ago

Could someone please list all of the basic derivative rules?

olchik [2.2K]

Answer:

The sum rule is f' + g'

The difference rule is f' − g'

The product rule is f g' + f' g

The quotient rule is (f' g − g' f )/g2

5 0

3 years ago