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Readme [11.4K]
3 years ago
11

Find the surface area of a cylinder with a base radius of 2 cm and a height of 3 cm.

Mathematics
1 answer:
jek_recluse [69]3 years ago
6 0

Answer: 62.8cm^2

Step-by-step explanation:

The surface area of a cylinder is calculated by 2πrh+2πr2

where π is a constant, given as 3.14; h is the height, given as 3cm and r is radius, given as 2cm.

Therefore, rh = 3 x 2= 6 cm ^2 while r^2 =2 × 2= 4 cm^2.

Slot the values into the formula:

V= 2 (3.14) x 6 + 2 (3.14) x 4

V=37.68 + 25.12

V=62.8cm ^2

I hope this helps

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A scale drawn on the map shows that 1 inch represents 20 miles. If two cities
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Answer:

50 miles

Step-by-step explanation:

20 multiplied by 2.5 = 50

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2 years ago
Which are the solutions of the quadratic equation? x2 = 9x + 6
Lelechka [254]
X^2 = 9x + 6
x^2 - 9x - 6 = 0
use quadratic formula : (-b (+-) sqrt b^2 - 4ac) / (2a)
a = 1, b = -9, c = -6
now we sub

x = (-(-9) (+-) sqrt -9^2 - 4(1)(-6)) / 2(1)
x = 9 (+-) sqrt 81 + 24)/2
x = 9 (+-) sqrt 105) / 2
x = 9/2 + 1/2 sqrt 105 or x = 9/2 - 1/2 sqrt 105

8 0
4 years ago
Read 2 more answers
Does anyone know the answer to this? I can't understand why it isn't -7.​
faltersainse [42]

The value of 18x + 9∆x - 7 based on the limit given will be 18x - 7.

<h3>How to calculate the value?</h3>

From the information given, it should be noted that we simply want to calculate the value of x.

This will be:

18x + 9∆x - 7

It was stated that ∆x = 0

Therefore, we'll put this into the equation.

This will be:

18x + 9∆x - 7

= 18x + 9(0) - 7

= 18x -7

Learn more about limit on:

brainly.com/question/12383223

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8 0
2 years ago
Find the perimeter of a square that is 3inches on a side. 7 inches 15 inches 12 inches 30 inches
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12 inches

Step-by-step explanation:

A square has 4 sides with the same length.

The perimeter of a square is the 4 times the length of one side.

perimeter = 4s

perimeter = 4 * 3 inches

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4 0
3 years ago
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Locate the absolute extrema of the function on the closed interval:<br> y = 3x^(2/3) - 2x, [-1, 1]
Alecsey [184]
To get the extrema, derive the function.
You get y' = 2x^-1/3 - 2.
Set this equal to zero, and you get x=0 as the location of a critical point.
Since you are on a closed interval [-1, 1], those points can also have an extrema.
Your min is right, but the max isn't at (1,1). At x=-1, you get y=5 (y = 3(-1)^2/3 -2(-1); (-1)^2/3 = 1, not -1).
Thus, the maximum is at (-1, 5).
7 0
3 years ago
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