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4 years ago

6

The spaces in bones are filled with a soft connective tissues called what

1 answer:

BaLLatris [955]4 years ago

6 0

Answer: cartilage
There are plenty different types of tissue found in bones such as bone marrow, endosteum, nerves, blood vessels, and of course cartilage.

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What are two differences between gravity and air resistance

Natalka [10]

1. Air resistance force usually upwards, but gravity doenwards.

2. Objects are affected by gravity the same, but air resistance can affect the speed of an object's descent.

Sorry if im wrong

4 0

3 years ago

A small styrofoam ball with a layer of metallic coating is lowered into the gap between two large metal plates. A large potentia

Brut [27]

Answer:

ball will oscillate in between the plates

Explanation:

The metallic coated styrofoam lowered in between two large metal plates, a large potential difference V is kept between the two plates, will experience a force of repulsion ( because both plates and balls will have similar kind of charges and like charges repel each other) from the opposite plates.

If we consider d as the distance between the plates, E as electric field because of Potential difference V. Then force F experience by the ball will be

$F= \frac{qV}{d}$

where q be the total charge on the metallic coated ball.

clearly, since, both the plates will repel the ball in opposite directions, hence ball will be in oscillate in between the plates.

3 0

4 years ago

ate around its central axis. A rope wrapped around the drum of radius 1.24 m exerts a force of 4.56 N to the right on the cylind

Mashcka [7]

Answer:

Magnitude the net torque about its axis of rotation is 1.3338 Nm

Explanation:

The radius of the wrapped rope around the drum, r = 1.24 m

Force applied to the right side of the drum, F = 4.56 N

The radius of the rope wrapped around the core, r' = 0.57 m

Force on the cylinder in the downward direction, F' = 7.58 N

Now, the magnitude of the net torque is given by:

$\tau_{net} = \tau + \tau'$

where

$\tau$ = Torque due to Force, F

$\tau'$ = Torque due to Force, F'

$\tau = F\times r\tau' = F'\times r'$

Now,

$\tau_{net} = - F\times r + F'\times r'\tau_{net} = - 4.56\times 1.24 + 7.58\times 0.57 \\\\= - 1.3338\ Nm$

The net torque comes out to be negative, this shows that rotation of cylinder is in the clockwise direction from its stationary position.

Now, the magnitude of the net torque:

$|\tau_{net}| = 1.3338\ Nm$

8 0

3 years ago

A cord is wrapped around the rim of a solid uniform wheel 0.280m in radius and of mass 8.80kg. A steady horizontal pull of 32N t

Grace [21]

Answer: $25.97 rad/s^2$

Explanation:

Given

radius of wheel $r=0.28 m$

mass of wheel $m=8.80 kg$

Force $F=32 N$

Moment of Inertia of solid wheel $I=\frac{mr^2}{2}$

$I=\frac{8.8\times 0.28^2}{2}$

$I=0.344 kg-m^2$

Torque is given by

$\tau =F\times r=I\times \alpha$

$32\times 0.28=0.344\times \alpha$

$\alpha =25.97 rad/s^2$

Force on the axle is 32 N since there is no linear acceleration of the system

using Third law F=32 N

Torque of the axle applied to the wheel is zero because force of axle imparted at the center of axle

3 0

3 years ago

Lf you divide a speed in miles per minute by 60, you get the same speed<br> expressed in miles per

Zielflug [23.3K]

Ok that is interesting.

8 0

3 years ago