According to the current, the charge is 818.18 coulombs.
We need to know about current to solve this problem. Current can be defined as the flow rate of charge through the medium. It can be determined as
I = Q / t
where I is current, Q is charge and t is time.
From the question above, we know that
P = 25 W
V = 110 V
h = 1 hour = 3600 second
Calculate the current
P = V . I
25 = 110 . I
I = 0.23 A
By substituting the given parameters, we can calculate the charge
I = Q / t
0.23 = Q / 3600
Q = 818.18 coulombs
Hence, the charge is 818.18 coulombs.
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Answer: An aspect of the event of various types of balls bouncing off the same floor, being matter is that all the balls consist of matter. They all occupy space and have a form of energy when moved by a force, such as a person. And for energy, like I just said, when they bounce they create energy as they bounce up and down, so if the ball were to hit some other object, it would have an impact on the still object.
The combination of the material properties of a ball (surface textures, actual materials, amount of air, hardness/ softness, and so on) affects the height of its bounce.
Hope this helps.......... Stay safe and have a Merry Christmas!!!!!!!!!! :D
Explanation:
Answer:
To reduce pressure - decrease the force or increase the area the force acts on. If you were standing on a frozen lake and the ice started to crack you could lie down to increase the area in contact with the ice. The same force (your weight) would apply, spread over a larger area, so the pressure would reduce.
Answer:
Animal Cells
Explanation:
they dont have cell walls because they dont need them. Wall cells are found in plants, which animals dont need.
Answer:
24volts
Explanation:
If a 15-µF capacitor is charged to 40V, the charge across the capacitor can be calculated using the formula;
Q = CV where;
Q is the charge flowing across the capacitor
C is the capacitance of the capacitor. = 15-µF
V is the voltage = 40V
Q = 15×10^-6×40
Q = 0.0006coulombs
If the charge of 0.0006coulombs is then connected across an initially uncharged 25-µF capacitor, the potential difference across the 25-µF can be calculated using the initial expression;
Q = CV
V = Q/C
V = 0.0006/25×10^-6
V = 24Volts
Therefore, the final potential difference across the 25-µF capacitor will be 24volts
