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user100 [1]
3 years ago
8

7. How much thermal energy is absorbed when 10.0 g of ice at 0.0 degrees C changes phase to liquid water at 0.0 degrees C? The m

olar mass, M, of water is 18.02 g/mol and the theoretical heat of fusion, Hfus, of water is 6.01 kJ/mol
Physics
1 answer:
Nesterboy [21]3 years ago
6 0

Answer:

3.34 kJ

Explanation:

FIrst of all, we need to calculate the number of moles corresponding to 10.0g of ice. This is given by

n=\frac{m }{M_m}

where

M_m = 18.02 g/mol is the molar mas

m = 10.0 g is the mass

Substituting

n=\frac{m}{M_m}=\frac{10 g}{18.02 g/mol}=0.555 mol

Now we know that the heat of fusion is

H_{fus}=6.01 kJ/mol

so the thermal energy needed to fuse the ice is

Q=n H_{fus} = (0.555 mol)(6.01 kJ/mol)=3.34 kJ

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3 years ago
Five identical quintuplets leave earth when they reach the age of 21, in the year 2121. Each quintuplet goes on a spaceship jour
Elena-2011 [213]

Answer:

Explanation:

This is a problem based on time dilation , a theory given by Albert Einstein .

The formula of time dilation is as follows .

t₁ = \frac{t}{\sqrt{1-\frac{v^2}{c^2} } }

t is time measured on the earth and t₁ is time measured by man on ship .

A ) Given t = 20 years , t₁ = ? v = .4c

\frac{20}{\sqrt{1-\frac{.16c^2}{c^2} } }

=1.09 x 20

t₁= 21.82 years

B ) Given t = 5 years , t₁ = ? v = .2c

\frac{5}{\sqrt{1-\frac{.04c^2}{c^2} } }

=1.02 x 5

t₁= 5.1 years

C ) Given t = 10 years , t₁ = ? v = .8c

\frac{10}{\sqrt{1-\frac{.64c^2}{c^2} } }

=1.67 x 10

t₁= 16.7  years

D ) Given t = 10 years , t₁ = ? v = .4c

\frac{10}{\sqrt{1-\frac{.16c^2}{c^2} } }

=1.09 x 10

t₁= 10.9  years

E ) Given t = 20 years , t₁ = ? v = .8c

\frac{20}{\sqrt{1-\frac{.64c^2}{c^2} } }

=1.67 x 20

t₁= 33.4   years

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The space between galaxies is continually ________________, thus causing the light from galaxies to become ____________. A. expa
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8 0
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I SERIOUSLY can't do this type of questions so can someone solve it detailedly and putting with letters (there is a system you n
KatRina [158]

Answer:

4 Ohms

Explanation

(This is seriously not as hard as it looks :)

You only need two types of calculations:

  1. replace two resistances, say, R1 and R2, connected in a series by a single one R. In this case the new R is a sum of the two: R = R_1+R_2
  2. replace two resistances that are connected in parallel. In that case: \frac{1}{R}= \frac{1}{R_1}+\frac{1}{R_2}\\\mbox{or}\\R= \frac{R_1\cdot R_2}{R_1+R_2}

I am attaching a drawing showing the process of stepwise replacement of two resistances at a time (am using rectangles to represent a resistance). The left-most image shows the starting point, just a little bit "warped" to see it better. The two resistances (6 Ohm next to each other) are in parallel and are replaced by a single resistance (3 Ohm, see formula above) in the top middle image. Next, the two resistances (9 and 3 Ohm) are nicely in series, so they can be replaced by their sum, which is what happened going to the top right image. Finally we have two resistances in parallel and they can be replaced by a single, final, resistance as shown in the bottom right image. That (4 Ohms) is the <em>equivalent resistance</em> of the original circuit.

Using these two transformations you will be able to solve step by step any  problem like this, no matter how complex.  

5 0
3 years ago
Starting from rest, a boulder rolls down a hill with constant acceleration and travels 3.00m during the first second.
Alexus [3.1K]

Answer:

a) 9.00 m b) 6.00 m/s  c) 12.00 m/s

Explanation:

a) If the acceleration is constant, and we know that the displacement during the first second was 3.00 m, as the boulder (assumed that we can treat it as a point mass) started from rest, we can say the following:

Δx = \frac{1}{2}*a*t^{2} = 3.00 m

As t = 1 s, replacing in the expression above, and solving for a, we have:

a = \frac{2*3.00m}{1s2} = 6.00 m/s²

In order to know how far it travels during the second second, we need to know the value of the speed after the first second, as it is the initial velocity when the second second begins:

vf = v₀ + a*t ⇒ vf = 0 + 6 m/s²*1s = 6.00 m/s

The total displacement, during the second second, will be as follows:

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⇒ Δx = 9.00 m

b) At the end of the first second, the final speed can be obtained as follows:

vf = v₀ + a*t ⇒ vf = 0 + 6 m/s²*1s = 6.00 m/s

c) At the end of the second second, the final speed can be obtained as follows:

vf = v₀ + a*t ⇒ vf = 0 + 6 m/s²*2s = 12.00 m/s

3 0
2 years ago
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