That right there is a line graph
The magnitude of the work done by the electric field of the membrane is <u>W = 1.28 × 10⁻²⁰ Joules</u>.
We start with the necessity to take into account a value for the voltage present there in order to solve this problem by first considering that the membranes have two layers, one internal and one external, each responsible for producing a potential difference between the two levels.
As a result, in order to find a solution, it is necessary to take into account the potential difference between the two surfaces. In this instance, we'll assume a particular value for the load, but the recipient is free to substitute a different value if they prefer.
The product of the potential difference and the charge is used to define the work that an electric field performs. The charge of the potassium ion will be equal to that of its electron, so,
q = 1.6 × 10⁻¹⁹ Coulombs
Then the Work would be:
W = Vq
Here,
v = Potential difference
q = Charge
The 80mV potential difference we will have is quantified as follows:
W = (80mV (1V/1000mV))( 1.6 × 10⁻¹⁹ C)
W = 1.28 × 10⁻²⁰ Joules is the amount of work that the membrane's electric field has produced.
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Answer:
The correct option is number 2. NADH is not product of light reactions of photosynthesis.
Explanation:
The light energy from the sun is captured by the pigmented molecule, chlorophyll, of the plants. This light energy is converted into chemical energy by a serious of light-dependent reactions. The main products of light-dependent reactions are the energy molecule ATP and NADPH. Oxygen is released as a by-product during photosynthesis. Hence, all the option 1,3 and 4 are produced during the light reactions except for option 2 i.e NADH.
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