Answer:
![m=\frac{-23}{3}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B-23%7D%7B3%7D)
![m=-7.6666666667](https://tex.z-dn.net/?f=m%3D-7.6666666667)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Slope Formula:
![m=\frac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
Step-by-step explanation:
<u>Step 1: Define</u>
Point (-1.25, -18.5)
Point (0.25, -30)
<u>Step 2: Find slope </u><em><u>m</u></em>
- Substitute:
![m=\frac{-30+18.5}{0.25+1.25}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B-30%2B18.5%7D%7B0.25%2B1.25%7D)
- Add:
![m=\frac{-11.5}{1.5}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B-11.5%7D%7B1.5%7D)
- Divide:
![m=\frac{-23}{3}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B-23%7D%7B3%7D)
Answer:
![\text{Selling price} = \$1000e^{5.6}](https://tex.z-dn.net/?f=%5Ctext%7BSelling%20price%7D%20%3D%20%5C%241000e%5E%7B5.6%7D)
The selling price of house is approximately 270.4264 thousand dollars.
Step-by-step explanation:
We are given the following in the question:
A linear model gives the relation between natural logarithm of price, in thousands of dollars, and size, in 100 square feet.
![\ln( \text{price})=2.08+0.11(\text{size})](https://tex.z-dn.net/?f=%5Cln%28%20%5Ctext%7Bprice%7D%29%3D2.08%2B0.11%28%5Ctext%7Bsize%7D%29)
Let p be the price and s be the size.
![\ln(p) = 2.08 + 0.11(s)](https://tex.z-dn.net/?f=%5Cln%28p%29%20%3D%202.08%20%2B%200.11%28s%29)
We have to approximate the selling price for a house with a size of 3,200 square feet.
Thus, we put s = 32
![\ln(p) = 2.08 + 0.11(32)\\\ln(p) = 5.6\\p = e^{5.6}\\p = 270.4264\\\text{Selling price} = \$1000e^{5.6}](https://tex.z-dn.net/?f=%5Cln%28p%29%20%3D%202.08%20%2B%200.11%2832%29%5C%5C%5Cln%28p%29%20%3D%205.6%5C%5Cp%20%3D%20e%5E%7B5.6%7D%5C%5Cp%20%3D%20270.4264%5C%5C%5Ctext%7BSelling%20price%7D%20%3D%20%5C%241000e%5E%7B5.6%7D)
Thus, the selling price of house is approximately 270.4264 thousand dollars.
Answer:
154,897 REGISTERED LABRADOR RETRIEVERS WERE THERE
Step-by-step explanation:
Given the statement: IN 1999, THERE WERE 9860 GREAT DANES REGISTERED WITH THE AMERICAN KENNEL CLUB.
Also, THE NUMBER OF REGISTERED LABRADOR RETRIEVERS WAS 6997 MORE THAN FIFTEEN TIMES THE NUMBER OF REGISTERED GREAT DANES
Let x represents the number of Great Danes registered and y represents the number of Labrador retrievers registered.
The statement:
"Fifteen times the number of registered great Danes " means 15x
and
"6997 more than fifteen times the number of registered great Danes" means 15x + 6997
then as per the given statement:
x = 9860 .
To solve for y;
y = 15x+ 6997
Substitute the value of x we get;
Simplify:
y = 154,897
Therefore, the registered Labrador Retrievers were there are; 154,897
douwdek0 and 16 more users found this answer helpful
Answer:
if you set b and a to the same number it would be equal to 2
Step-by-step explanation:
Answer:
$1.68
Step-by-step explanation:
Remember that cents are in the hundredths place. So think of it as rounding to the nearest hundredth place. 1.6845 ---> 1.68