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vlada-n [284]
3 years ago
5

The perimeter of the rectangular playing field is 430 yards.The length of the field is 5 yards less than triple the width. What

are the dimensions of the playing​ field?
Mathematics
2 answers:
Ad libitum [116K]3 years ago
6 0

Answer:

Length = 160 and width = 55 yards

Step-by-step explanation:

Perimeter =  2L + 2W  where L = the length and W = the width.

L = 3W - 5   (given).

So substituting for L is the formula for the perimeter:-

2(3W - 5) + 2W = 430

6W - 10 + 2W = 430

8W = 440

W = 55 yards.

So the Length L = [430 - 2(55]) / 2  = 160 yards.


svlad2 [7]3 years ago
3 0

Answer:

Answer - 160

Step-by-step explanation:

2L+2W = 430

L = 3W-5

2(3W-5)+2W = 430

6W-10+2W = 430

8W = 440

W = 55 and L = 3(55)-5 = 160

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For the functions f(x)=2x^2+3x+9 and g(x)=−3x+10 find (f⋅g)(x) and (f⋅g)(1)
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Step-by-step explanation:

f(x)=2x²+3x+9

g(x) = - 3x + 10

In order to find (f⋅g)(1) first find (f⋅g)(x)

To find (f⋅g)(x) substitute g(x) into f(x) , that's for every x in f (x) replace it by g (x)

We have

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(f⋅g)(x) = 2( 9x² - 60x + 100) - 9x + 30 + 9

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Group like terms

(f⋅g)(x) = 18x² - 120x - 9x + 200 + 30 + 9

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To find (f⋅g)(1) substitute 1 into (f⋅g)(x)

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